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ORACLE 表中的以下结构:

FILE_NAME
-----------
12345_l.tif
12345_m.tif
12345_r.tif
12345_x.tif
12345_y.tif

需要以下结果:

First *_m*
Then *_l*
Then *_r*
Then * (everything else)

尝试:

SELECT FILE_NAME FROM TABLE
WHERE FILE_NAME LIKE '12345%'
ORDER BY regexp_replace(FILE_NAME, '_m', '_1'),
         regexp_replace(FILE_NAME, '_l', '_2'),
         regexp_replace(FILE_NAME, '_r', '_3')

但这给了我一个错误的结果。

有人有提示吗?

TIA 马特

4

1 回答 1

2

更改您的 ORDER BY 以按数字排序:

 ORDER BY regexp_replace(FILE_NAME, '_m', 1),
          regexp_replace(FILE_NAME, '_l', 2),
          regexp_replace(FILE_NAME, '_r', 3);

例如

WITH t
  AS (SELECT '12345_l.tif' AS file_name FROM dual
      UNION
      SELECT '12345_m.tif' FROM dual
      UNION
      SELECT '12345_r.tif' FROM dual
      UNION
      SELECT '12345_x.tif' FROM dual
      UNION
      SELECT '12345_y.tif' FROM dual)
SELECT file_name
  FROM t
 ORDER BY regexp_replace(FILE_NAME, '_m', 1),
          regexp_replace(FILE_NAME, '_l', 2),
          regexp_replace(FILE_NAME, '_r', 3);

给出:

==============
12345_m.tif
12345_l.tif
12345_r.tif
12345_x.tif
12345_y.tif

希望能帮助到你...

或者,您可以使用:

 ORDER BY (CASE SUBSTR(file_name, INSTR(file_name, '_')+1, 1)
             WHEN 'm' THEN 1
             WHEN 'l' THEN 2
             WHEN 'r' THEN 3
             ELSE 4
            END) ASC;

例如:

WITH t
  AS (SELECT '12345_l.tif' AS file_name FROM dual
      UNION
      SELECT '12345_y.tif' FROM dual
      UNION
      SELECT '12345_r.tif' FROM dual
      UNION
      SELECT '12345_x.tif' FROM dual
      UNION
      SELECT '12345_m.tif' FROM dual)
SELECT file_name
  FROM t
 ORDER BY (CASE SUBSTR(file_name, INSTR(file_name, '_')+1, 1)
             WHEN 'm' THEN 1
             WHEN 'l' THEN 2
             WHEN 'r' THEN 3
             ELSE 4
            END) ASC;

给出:

12345_m.tif
12345_l.tif
12345_r.tif
12345_x.tif
12345_y.tif
于 2012-04-27T12:15:56.817 回答