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我有以下 jquery 函数来解析 json 数组“projectDetail”，但是当我尝试从数组中打印 ApprovalDesc 的值时，它显示为未定义，请问我知道什么是正确的语法吗？

function show(projectDetail) {
          var  project = projectDetail;
            $.each(project, function (i, tweet) {
                $.each(tweet.ProjectUpdates, function (i, tweet1) {
                $.each(tweet1.ProjectApproval, function (i, tweet2) {
                alert(i + ': ' + tweet2.ApprovalDesc);
               var PStatus = tweet.ApprovalDesc;
            });
        });
        });
       }

json输出

{ "d" : {
      "ProjectUpdates" : { "ExceptionId" : 0,
          "ProjectApproval" : [ { "ApprovalDesc" : "ABCApproved",
                "CreatedBy" : null,
                "CreatedDate" : "/Date(-62135596800000)/", 
                "ModifiedDate" : "/Date(-62135596800000)/",
                "ApprovalDesc" : "welcome",
                "SortOrder" : 1
              } ],
          "ProjectStatusGallery" : [ { "CategoryId" : 0,
                "CreatedBy" : null,
                "CreatedDate" : "/Date(-62135596800000)/",              
                "ImageName" : "flower",
                "ImageUrl" : "D://Images",
                "ModifiedBy" : null,
                "ModifiedDate" : "/Date(-62135596800000)/",               
              },
              { "CategoryId" : 0,
                "CreatedBy" : null,
                "CreatedDate" : "/Date(-62135596800000)/",                
                "ImageName" : "flower2",
                "ImageUrl" : "D://Images",
                "ModifiedBy" : null,
                "ModifiedDate" : "/Date(-62135596800000)/"                
              }
            ]
        },
 "__type" : "sample"
    } }
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2 回答 2

1

欢迎应该被引用为一个字符串。

于 2012-04-26T11:58:39.050 回答
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您是否在 json 字符串上调用了 parseJSON 以将其放入对象中？然后它很容易访问，不需要循环。

http://api.jquery.com/jQuery.parseJSON/

var json = $.parseJSON(your_json_string);

console.log(json.__type.sample);
console.log(json.d.ProjectUpdates.ProjectStatusGallery.ImageName);
于 2012-04-26T11:57:30.733 回答