1

我有一个页面显示用户已保存到 MYSQL 数据库的项目，并将其与复选框一起显示出来。我希望当用户单击此复选框并单击保存按钮时，记录将被删除，但我的标题中出现错误。

显示假期表格。

        <form action="deleteProcess.php">
<?php
        foreach($db->query($sql) as $row)
        {
            echo "<p>" . $row['title'] . "<br \>" . 
                         $row['description'] . "<br \>" . 
                         $row['link'] . "<br \>" .
                         $row['pubDate'] . 
                         "<input type='checkbox' name='del[]' value='$row/['title'/]'/>" . 
                         "</p>";    
        }
?>
        <input type="submit" name="delete" value="submit" />
        </form>

删除process.php

foreach($_POST['del'] as $check_value)
        {
            //takes session value and assigns it to a variable so that when a holiday is saved it can be distinguished by user
            $user = $_SESSION['name'];
            //assign the value of previous checkbox to $check
            $check = $check_value;
            //assign xpath query to variable $fav
            $fav = "channel/item [title = \"$check\"]";
            //loads instance of xml file as $holidayDoc
            $holidayDoc = simplexml_load_file('holidays.xml');
            //executes xpath search within holidays.xml and results stored in $favourites
            $favourites = $holidayDoc->xpath($fav);

        //for each element of the associative array $favourites, key will be referred to as $currentFav. 
        foreach($favourites as $currentFav)
        {
            echo "{$currentFav->link}". "<br \>";
            echo "{$currentFav->title}". "<br \>";
            echo "{$currentFav->description}". "<br \>";
            echo "{$currentFav->pubDate} ". "<br \>";
            //sql statement that states which values will be inserted into which column
            $sql = "DELETE FROM `saved_holidays` (`subscriberID`, `link`, `pubDate`, `title`, `description`) 
        VALUES ('$user', '$currentFav->link', '$currentFav->pubDate', '$currentFav->title', '$currentFav->description')";

            //connect to database then execute the sql statement.
            $db->exec($sql);
            //close connection to the database
            $db = null;

错误显示foreach($_POST['del'] as $check_value)在线路上，我无法理解为什么它不起作用，任何帮助将不胜感激。

注意：未定义索引：第 14 行 /var/www/vhosts/numyspace.co.uk/web_users/home/~unn_w11026991/public_html/Ass/deleteProcess.php 中的删除

警告：在第 14 行的 /var/www/vhosts/numyspace.co.uk/web_users/home/~unn_w11026991/public_html/Ass/deleteProcess.php 中为 foreach() 提供的参数无效

4

6 回答 6

3

您的del复选框根本没有从表单中发布。您需要添加method="post"到您的表单中。

<form action="deleteProcess.php" method="post">

于 2012-04-26T10:22:17.240 回答
1

您应该首先检查是否设置了 $_POST['del'] 因为如果没有选中复选框，则不会。

if(isset($_POST['del'])){
    foreach($_POST['del'] as $del){}
}
于 2012-04-26T10:21:47.340 回答
1

您通过 $_POST 访问您的复选框值，但您的 Form-Tag 没有定义方法！你必须设置<form method="POST">，否则你必须使用$_GET['del']

于 2012-04-26T10:22:24.427 回答
1

method="post"中缺少<form action。

您的删除 SQL 语法也不正确。从数据库中删除记录时，您不指定列。您删除了整条记录。

删除语法是：

DELETE FROM table_name WHERE condition
于 2012-04-26T10:23:21.343 回答
1

您的表格中缺少method="post"您，因此没有发布任何内容，这是您的问题。

于 2012-04-26T10:24:56.637 回答
0

这个错误很明显。

$_POST['del']

不存在，因为del它不是已发布表单的有效字段。

如果del是复选框的名称，您首先必须通过添加post action到您的表单来检索它们

于 2012-04-26T10:23:22.290 回答