2

这是我的桌子：

我的表：Id, Title, Point, Date

所以我需要检查所有的点和日期Title = 'member1'是否等于所有的点和日期Title = 'member2'然后Set @flag = 1否则Set @flag = 0确切的两个选择是：

Select Point, Date From MyTable Where Title = 'member1'

和

Select Point, Date From MyTable Where Title = 'member2'

我需要检查所有行是否相等。你的建议是什么？

更新：

假设以下示例：

Title  Point     Date

T1      1   2012-04-26 07:14:34.000
T1      2   2012-07-26 07:14:34.000
T1      3   2012-06-26 07:14:34.000
T1      4   2012-05-26 07:14:34.000
T2      1   2012-04-26 07:14:34.000
T2      2   2012-07-26 07:14:34.000
T2      3   2012-06-26 07:14:34.000
T2      4   2012-05-26 07:14:34.000
T3      4   2012-05-26 07:14:34.000
T3      3   2012-06-26 07:14:34.000
T4      1   2012-04-26 07:14:34.000
T4      2   2012-07-26 07:14:34.000
T4      3   2012-06-26 07:14:34.000
T4      4   2012-05-27 07:14:34.000 -- 26 to 27
T5      2   2012-12-27 07:14:34.000
T5      6   2012-05-27 07:14:34.000
T5      3   2012-07-26 07:14:34.000

在此示例中，只有 T1 值和 T2 值相等，而其他值不相等。

4

3 回答 3

1

这是我将如何做到的。计划是获取每个结果集，然后将其转换为 XML 并比较两个 XML 结果。容易得多（在我看来）。

CREATE TABLE MyTable
(
[id] integer identity,
[Title] varchar(1024),
[Point] int,
[Date] datetime
);


insert into MyTable([Title], [Point], [Date])
values('T1',      1,   '2012-04-26 07:14:34.000'),
('T1',      2,   '2012-07-26 07:14:34.000'),
('T1',      3,   '2012-06-26 07:14:34.000'),
('T1',      4,   '2012-05-26 07:14:34.000'),
('T2',      1,   '2012-04-26 07:14:34.000'),
('T2',      2,   '2012-07-26 07:14:34.000'),
('T2',      3,   '2012-06-26 07:14:34.000'),
('T2',      4,   '2012-05-26 07:14:34.000'),
('T3',      4,   '2012-05-26 07:14:34.000'),
('T3',      3,   '2012-06-26 07:14:34.000'),
('T4',      1,   '2012-04-26 07:14:34.000'),
('T4',      2,   '2012-07-26 07:14:34.000'),
('T4',      3,   '2012-06-26 07:14:34.000'),
('T4',      4,   '2012-05-27 07:14:34.000'),
('T5',      2,   '2012-12-27 07:14:34.000'),
('T5',      6,   '2012-05-27 07:14:34.000'),
('T5',      3,   '2012-07-26 07:14:34.000');

-- your original queries
Select Point, Date From MyTable Where Title = 'T1';
Select Point, Date From MyTable Where Title = 'T2';

-- first I am going to just get each one as XML
SELECT [Point], [Date]
FROM MyTable 
WHERE Title = 'T1'
FOR XML PATH('');


SELECT [Point], [Date]
FROM MyTable 
WHERE Title = 'T2'
FOR XML PATH('');



-- first just get the two results into one result set
select t.FirstCheck, t.SecondCheck
from (
    select (SELECT [Point], [Date]
              FROM MyTable 
             WHERE Title = 'T1'
               FOR XML PATH('')) as FirstCheck,
           (SELECT [Point], [Date]
              FROM MyTable 
             WHERE Title = 'T2'
               FOR XML PATH('')) as SecondCheck
) as t;


-- now for the real check.

declare @flag int;

select @flag = case when t.FirstCheck = t.SecondCheck  then 1 else 0 end 
from (
    select (SELECT [Point], [Date]
              FROM MyTable 
             WHERE Title = 'T1'
               FOR XML PATH('')) as FirstCheck,
           (SELECT [Point], [Date]
              FROM MyTable 
             WHERE Title = 'T2'
               FOR XML PATH('')) as SecondCheck
) as t;
-- this should return 1
select @flag as Flag;


select @flag = case when t.FirstCheck = t.SecondCheck  then 1 else 0 end 
from (
    select (SELECT [Point], [Date]
              FROM MyTable 
             WHERE Title = 'T1'
               FOR XML PATH('')) as FirstCheck,
           (SELECT [Point], [Date]
              FROM MyTable 
             WHERE Title = 'T3'
               FOR XML PATH('')) as SecondCheck
) as t;
-- this should return 0
select @flag as Flag;

如果我了解您要做什么，那么应该这样做。

于 2012-04-29T01:19:34.753 回答
1

我猜您需要检查成员 2 中是否缺少成员 1，反之亦然，因此您需要同时检查两种方式。如果您在一系列日期之间执行此操作（下面的代码将是所有日期），则可以使用整数表一次性完成，并且效率更高。

IF NOT EXISTS (
SELECT
    Point,
    Date
FROM 
    MyTable aa
LEFT OUTER JOIN MyTable bb
ON aa.point = bb.point
AND aa.date = bb.date

WHERE 
    aa.title = 'member1'
AND bb.title = 'member2'
AND bb.title IS NULL

UNION 

SELECT
    Point,
    Date
FROM 
    MyTable aa
LEFT OUTER JOIN MyTable bb
ON aa.point = bb.point
AND aa.date = bb.date

WHERE 
    aa.title = 'member2'
AND bb.title = 'member1'
AND bb.title IS NULL
)
SELECT @Flag = 1
于 2012-04-26T07:04:20.580 回答
0

这不会赢得任何选美或表演比赛，但应该足够了。它的要点是

  • 获取每个标题的计数
  • MyTable在您喜欢比较的所有字段上加入自身
  • 将两者加入各自的计数表
  • 仅选择两个计数匹配的结果

SQL 语句

;WITH cnt (Title, cnt) AS (
  SELECT  Title, COUNT(*)
  FROM    MyTable
  GROUP BY
          Title
)  
SELECT  DISTINCT mt1.Title
        , mt2.Title
FROM    MyTable mt1
        INNER JOIN MyTable mt2 ON mt1.Point = mt2.Point 
                                  AND mt1.Date = mt2.Date 
                                  AND mt1.Title < mt2.Title
        INNER JOIN cnt cnt1 ON cnt1.Title = mt1.Title
        INNER JOIN cnt cnt2 ON cnt2.Title = mt2.Title        
WHERE   cnt1.cnt = cnt2.cnt
于 2012-04-26T07:53:22.053 回答