总的来说,我会使用 push 方法而不是传递变量,从而减少从中间被黑客入侵的机会。
我的 http 调用的 AS3 代码:
public function someRequest() : void
{
var service : HTTPService = new HTTPService();
service.url = "http://localhost/getData.php";
service.useProxy = false;
service.method = "POST";
service.contentType = "application/xml"; // Pass XML data.
service.request = "<ID>somevalue</ID>"; // The XML data.
service.resultFormat = "xml"; // Recieve XML data.
service.addEventListener(ResultEvent.RESULT, createFields);
service.addEventListener(FaultEvent.FAULT, handleFault);
service.send();
}
private function createFields(event : ResultEvent) : void
{
var result : String = event.result.toString();
returnData = XML(result);
}
private function handleFault(event : FaultEvent) : void
{
var faultstring : String = event.fault.faultString;
Alert.show(faultstring);
}
正如您在中间看到的,有一个用于输入变量的 XML 空间。我使用这种方法从 PHP 到 AS3 来回传递数据。
PHP 是:
<?php
define("DATABASE_SERVER", "localhost");
define("DATABASE_USERNAME", "root");
define("DATABASE_PASSWORD", "**");
define("DATABASE_NAME", "dbName");
//connect to the database.
$mysql = mysql_connect(DATABASE_SERVER, DATABASE_USERNAME, DATABASE_PASSWORD);
mysql_select_db(DATABASE_NAME);
$Query = "SELECT * from data WHERE employeeID = '" . ($_POST['ID']) . "'";
$Result = mysql_query($Query);
$Return = "<data>";
while ($User = mysql_fetch_object($Result))
{
$Return .= "<user><userid>" . $User->userid . "</userid><username>" . $User->username . "</username><emailaddress>" . $User->emailaddress . "</emailaddress></user>";
}
$Return .= "</data>";
mysql_free_result($Result);
print ($Return)
?>
希望对您有所帮助。