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我如何使用 php 从 xml 页面获取内容。内容如下：

 <entry>
   <title>News</title>
     <link rel="alternate" href="http://www.website.com/detail/2688327:BlogPost:1569917"/>
     <id>tag:www.website.com,2012-04-25:2688327:BlogPost:1569917</id>
     <updated>2012-04-25T08:30:00.000Z</updated>
     <author>
     <name>Username</name>
     <uri>http://www.website.com/profile/username</uri>
     </author>
      <summary type="html">
      Hi this is the latest news
      </summary>
</entry>

 <entry>
   <title>News2</title>
     <link rel="alternate" href="http://www.website.com/detail/2688327:BlogPost:1569917"/>
     <id>tag:www.website.com,2012-04-25:2688327:BlogPost:1569917</id>
     <updated>2012-04-25T08:30:00.000Z</updated>
     <author>
     <name>Username2</name>
     <uri>http://www.website.com/profile/username</uri>
     </author>
      <summary type="html">
      Hi this is the latest news
      </summary>
</entry>

 <entry>
   <title>News3</title>
     <link rel="alternate" href="http://www.website.com/detail/2688327:BlogPost:1569917"/>
     <id>tag:www.website.com,2012-04-25:2688327:BlogPost:1569917</id>
     <updated>2012-04-25T08:30:00.000Z</updated>
     <author>
     <name>Username3</name>
     <uri>http://www.website.com/profile/username</uri>
     </author>
      <summary type="html">
      Hi this is the latest news
      </summary>
</entry>

 <entry>
   <title>News4</title>
     <link rel="alternate" href="http://www.website.com/detail/2688327:BlogPost:1569917"/>
     <id>tag:www.website.com,2012-04-25:2688327:BlogPost:1569917</id>
     <updated>2012-04-25T08:30:00.000Z</updated>
     <author>
     <name>Username4</name>
     <uri>http://www.website.com/profile/username</uri>
     </author>
      <summary type="html">
      Hi this is the latest news
      </summary>
</entry>

如何<link rel="alternate" href="http://www.website.com/detail/2688327:BlogPost:1569917"/>使用 php 获取标题、博客链接、作者详细信息（如姓名和 uri（个人资料链接）以及摘要）的数组？

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1 回答 1

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查看 simplexml，xpath http://php.net/manual/en/book.simplexml.php

   $file = 'url or file name';
    $xml = simplexml_load_file('$file');
    $list= $xml->xpath("/entry"); // root/entry ...
    print $list[0]->id; 
    #var_dump($list);
于 2012-04-25T10:28:32.130 回答