0

我有这个查询：

SELECT 
    s.last_spread, s.sd, s.mean, s.id
    ,c.id_ticker, c.coef
    ,t.ticker
    ,/*p.last,*/ p.price

FROM (SELECT * FROM spreads WHERE spreads.id_check=1 LIMIT 60,896) as s 

    INNER JOIN coef as c 
        ON c.id_spread = s.id

    INNER JOIN tickers AS t
            ON t.id = c.id_ticker

    LEFT JOIN (SELECT prices.id_ticker, MAX(prices.date) as last, prices.price FROM prices GROUP BY prices.id_ticker) AS p
            ON p.id_ticker = t.id

ORDER BY s.id, c.id

最后一个 JOIN 没有返回正确的值....我需要获取代码的最后价格（所以每个代码的最后一行）。

在它返回第一个价格的那一刻，我如何更改整个查询以获取每个 ticker.id 的最后价格？( p.id_ticker = t.id)

谢谢！

4

3 回答 3

3

向此子查询添加 order by：

SELECT prices.id_ticker, MAX(prices.date) as last, prices.price 
FROM prices GROUP BY prices.id_ticker 
order by prices.id_ticker desc
于 2012-04-25T08:52:38.603 回答
2

使用 Ahaving 子句会很优雅：

LEFT JOIN (SELECT prices.id_ticker, prices.date as last, prices.price FROM prices GROUP BY prices.id_ticker HAVING prices.date = MAX(prices.date) )

编辑：但它不起作用......（见下面的评论）

于 2012-04-25T08:55:55.250 回答
1

我会说 useORDER BY和 aLIMIT只得到一个价格（最后一个价格）。

于 2012-04-25T08:56:08.510 回答