258

我正在开发 Android 操作系统上的应用程序。我不知道如何检查位置服务是否启用。

我需要一个方法，如果启用它们，则返回“true”，否则返回“false”（因此在最后一种情况下，我可以显示一个对话框来启用它们）。

4

22 回答 22

404

您可以使用以下代码检查是否启用了 gps 提供商和网络提供商。

LocationManager lm = (LocationManager)context.getSystemService(Context.LOCATION_SERVICE);
boolean gps_enabled = false;
boolean network_enabled = false;

try {
    gps_enabled = lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
} catch(Exception ex) {}

try {
    network_enabled = lm.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
} catch(Exception ex) {}

if(!gps_enabled && !network_enabled) {
    // notify user
    new AlertDialog.Builder(context)
        .setMessage(R.string.gps_network_not_enabled)
        .setPositiveButton(R.string.open_location_settings, new DialogInterface.OnClickListener() {
            @Override
            public void onClick(DialogInterface paramDialogInterface, int paramInt) {
                context.startActivity(new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS));
            }
        })
        .setNegativeButton(R.string.Cancel,null)
        .show();    
}

在清单文件中，您将需要添加以下权限

<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION"/>
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>
于 2012-04-25T08:18:22.243 回答
230

我使用此代码进行检查：

public static boolean isLocationEnabled(Context context) {
    int locationMode = 0;
    String locationProviders;

    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT){
        try {
            locationMode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE);

        } catch (SettingNotFoundException e) {
            e.printStackTrace();
            return false;
        }

        return locationMode != Settings.Secure.LOCATION_MODE_OFF;

    }else{
        locationProviders = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
        return !TextUtils.isEmpty(locationProviders);
    }


}
于 2014-04-10T07:00:53.927 回答
72

就像现在在 2020 年一样

最新，最好和最短的方法是

@SuppressWarnings("deprecation")
public static Boolean isLocationEnabled(Context context) {
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) {
        // This is a new method provided in API 28
        LocationManager lm = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
        return lm.isLocationEnabled();
    } else {
        // This was deprecated in API 28
        int mode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE,
                Settings.Secure.LOCATION_MODE_OFF);
        return (mode != Settings.Secure.LOCATION_MODE_OFF);
    }
}
于 2019-02-12T11:11:52.427 回答
56

迁移到 AndroidX 并使用

implementation 'androidx.appcompat:appcompat:1.3.0'

并使用 LocationManagerCompat

在 Java 中

private boolean isLocationEnabled(Context context) {
    LocationManager locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
    return LocationManagerCompat.isLocationEnabled(locationManager);
}

在科特林

private fun isLocationEnabled(context: Context): Boolean {
    val locationManager = context.getSystemService(Context.LOCATION_SERVICE) as LocationManager
    return LocationManagerCompat.isLocationEnabled(locationManager)
}
于 2019-09-26T04:03:15.777 回答
38

您可以使用此代码将用户引导至设置，他们可以在其中启用 GPS：

    locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
    if( !locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER) ) {
        new AlertDialog.Builder(context)
            .setTitle(R.string.gps_not_found_title)  // GPS not found
            .setMessage(R.string.gps_not_found_message) // Want to enable?
            .setPositiveButton(R.string.yes, new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialogInterface, int i) {
                    owner.startActivity(new Intent(android.provider.Settings.ACTION_LOCATION_SOURCE_SETTINGS));
                }
            })
            .setNegativeButton(R.string.no, null)
            .show();
    }
于 2012-04-25T08:17:34.610 回答
15

根据上面的答案，在 API 23 中，您需要添加“危险”权限检查以及检查系统本身：

public static boolean isLocationServicesAvailable(Context context) {
    int locationMode = 0;
    String locationProviders;
    boolean isAvailable = false;

    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT){
        try {
            locationMode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE);
        } catch (Settings.SettingNotFoundException e) {
            e.printStackTrace();
        }

        isAvailable = (locationMode != Settings.Secure.LOCATION_MODE_OFF);
    } else {
        locationProviders = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
        isAvailable = !TextUtils.isEmpty(locationProviders);
    }

    boolean coarsePermissionCheck = (ContextCompat.checkSelfPermission(context, Manifest.permission.ACCESS_COARSE_LOCATION) == PackageManager.PERMISSION_GRANTED);
    boolean finePermissionCheck = (ContextCompat.checkSelfPermission(context, Manifest.permission.ACCESS_FINE_LOCATION) == PackageManager.PERMISSION_GRANTED);

    return isAvailable && (coarsePermissionCheck || finePermissionCheck);
}
于 2016-04-15T16:15:44.143 回答
9

是的，您可以检查以下代码：

public boolean isGPSEnabled(Context mContext) 
{
    LocationManager lm = (LocationManager)
    mContext.getSystemService(Context.LOCATION_SERVICE);
    return lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
}

使用清单文件中的权限：

<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />
于 2015-03-19T08:31:46.440 回答
7

如果未启用提供程序，则“被动”是返回的最佳提供程序。见https://stackoverflow.com/a/4519414/621690

    public boolean isLocationServiceEnabled() {
        LocationManager lm = (LocationManager)
                this.getSystemService(Context.LOCATION_SERVICE);
        String provider = lm.getBestProvider(new Criteria(), true);
        return (StringUtils.isNotBlank(provider) &&
                !LocationManager.PASSIVE_PROVIDER.equals(provider));
    }
于 2014-02-06T16:28:15.817 回答
6

在我看来，这个 if 子句很容易检查位置服务是否可用：

LocationManager locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
if(!locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER) && !locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)) {
        //All location services are disabled

}
于 2014-01-09T11:33:45.840 回答
4

要在 android 谷歌地图中获取当前地理位置，您应该打开您的设备位置选项。要检查该位置是否打开，您可以简单地从您的方法中调用此onCreate()方法。

private void checkGPSStatus() {
    LocationManager locationManager = null;
    boolean gps_enabled = false;
    boolean network_enabled = false;
    if ( locationManager == null ) {
        locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
    }
    try {
        gps_enabled = locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER);
    } catch (Exception ex){}
    try {
        network_enabled = locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
    } catch (Exception ex){}
    if ( !gps_enabled && !network_enabled ){
        AlertDialog.Builder dialog = new AlertDialog.Builder(MyActivity.this);
        dialog.setMessage("GPS not enabled");
        dialog.setPositiveButton("Ok", new DialogInterface.OnClickListener() {

            @Override
            public void onClick(DialogInterface dialog, int which) {
                //this will navigate user to the device location settings screen
                Intent intent = new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS);
                startActivity(intent);
            }
        });
        AlertDialog alert = dialog.create();
        alert.show();
    }
}
于 2014-11-19T04:23:34.773 回答
4

这是一个非常有用的方法，true如果Location services启用，则返回“”：

public static boolean locationServicesEnabled(Context context) {
        LocationManager lm = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
        boolean gps_enabled = false;
        boolean net_enabled = false;

        try {
            gps_enabled = lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
        } catch (Exception ex) {
            Log.e(TAG,"Exception gps_enabled");
        }

        try {
            net_enabled = lm.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
        } catch (Exception ex) {
            Log.e(TAG,"Exception network_enabled");
        }
        return gps_enabled || net_enabled;
}
于 2016-02-09T23:53:15.223 回答
4

对于科特林

 private fun isLocationEnabled(mContext: Context): Boolean {
    val lm = mContext.getSystemService(Context.LOCATION_SERVICE) as LocationManager
    return lm.isProviderEnabled(LocationManager.GPS_PROVIDER) || lm.isProviderEnabled(
            LocationManager.NETWORK_PROVIDER)
 }

对话

private fun showLocationIsDisabledAlert() {
    alert("We can't show your position because you generally disabled the location service for your device.") {
        yesButton {
        }
        neutralPressed("Settings") {
            startActivity(Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS))
        }
    }.show()
}

像这样打电话

 if (!isLocationEnabled(this.context)) {
        showLocationIsDisabledAlert()
 }

提示：对话框需要以下导入（android studio 应该为你处理这个）

import org.jetbrains.anko.alert
import org.jetbrains.anko.noButton

在清单中，您需要以下权限

<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION"/>
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>
于 2018-06-29T12:14:14.890 回答
4

我对NETWORK_PROVIDER使用这种方式，但您可以为GPS添加和。

LocationManager locationManager;

在onCreate我放

   isLocationEnabled();
   if(!isLocationEnabled()) {
        AlertDialog.Builder builder = new AlertDialog.Builder(MainActivity.this);
        builder.setTitle(R.string.network_not_enabled)
                .setMessage(R.string.open_location_settings)
                .setPositiveButton(R.string.yes,
                        new DialogInterface.OnClickListener() {
                            public void onClick(DialogInterface dialog, int id) {
                                startActivity(new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS));
                            }
                        })
                .setNegativeButton(R.string.cancel,
                        new DialogInterface.OnClickListener() {
                            public void onClick(DialogInterface dialog, int id) {
                                dialog.cancel();
                            }
                        });
        AlertDialog alert = builder.create();
        alert.show();
    }

及检查方法

protected boolean isLocationEnabled(){
    String le = Context.LOCATION_SERVICE;
    locationManager = (LocationManager) getSystemService(le);
    if(!locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)){
        return false;
    } else {
        return true;
    }
}
于 2015-12-10T11:06:54.067 回答
3

我使用第一个代码开始创建方法 isLocationEnabled

 private LocationManager locationManager ;

protected boolean isLocationEnabled(){
        String le = Context.LOCATION_SERVICE;
        locationManager = (LocationManager) getSystemService(le);
        if(!locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)){
            return false;
        } else {
            return true;
        }
    }

我检查条件如果真的打开地图和错误给出意图 ACTION_LOCATION_SOURCE_SETTINGS

    if (isLocationEnabled()) {
        SupportMapFragment mapFragment = (SupportMapFragment) getSupportFragmentManager()
                .findFragmentById(R.id.map);
        mapFragment.getMapAsync(this);

        locationClient = getFusedLocationProviderClient(this);
        locationClient.getLastLocation()
                .addOnSuccessListener(new OnSuccessListener<Location>() {
                    @Override
                    public void onSuccess(Location location) {
                        // GPS location can be null if GPS is switched off
                        if (location != null) {
                            onLocationChanged(location);

                            Log.e("location", String.valueOf(location.getLongitude()));
                        }
                    }
                })
                .addOnFailureListener(new OnFailureListener() {
                    @Override
                    public void onFailure(@NonNull Exception e) {
                        Log.e("MapDemoActivity", e.toString());
                        e.printStackTrace();
                    }
                });


        startLocationUpdates();

    }
    else {
        new AlertDialog.Builder(this)
                .setTitle("Please activate location")
                .setMessage("Click ok to goto settings else exit.")
                .setPositiveButton(android.R.string.yes, new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog, int which) {
                        Intent intent = new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS);
                        startActivity(intent);
                    }
                })
                .setNegativeButton(android.R.string.no, new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog, int which) {
                        System.exit(0);
                    }
                })
                .show();
    }

在此处输入图像描述

于 2018-02-26T12:08:14.497 回答
3

在 Android 8.1 或更低版本上，用户可以从
Settings > Location > Mode > Battery Saving.
此模式仅使用WiFi, Bluetooth or mobile data而不是 GPS 来确定用户位置。

这就是为什么您必须检查网络提供商是否已启用并且locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER)还不够。

如果您使用androidx此代码，将检查您正在运行的 SDK 版本并调用相应的提供程序：

public boolean isLocationEnabled(Context context) {
    LocationManager manager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
    return manager != null && LocationManagerCompat.isLocationEnabled(manager);
}
于 2020-09-09T02:39:33.650 回答
2 
private boolean isGpsEnabled()
{
    LocationManager service = (LocationManager) getSystemService(LOCATION_SERVICE);
    return service.isProviderEnabled(LocationManager.GPS_PROVIDER)&&service.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
}
于 2014-08-13T11:11:35.773 回答
2

可以用最简单的方式做

private boolean isLocationEnabled(Context context){
int mode =Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE,
                        Settings.Secure.LOCATION_MODE_OFF);
                final boolean enabled = (mode != android.provider.Settings.Secure.LOCATION_MODE_OFF);
return enabled;
}
于 2018-12-19T06:11:40.043 回答
2 
public class LocationUtil {
private static final String TAG = LocationUtil.class.getSimpleName();

public static LocationManager getLocationManager(final Context context) {
    return (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
}

public static boolean isNetworkProviderEnabled(final Context context) {
    return getLocationManager(context).isProviderEnabled(LocationManager.NETWORK_PROVIDER);
}

public static boolean isGpsProviderEnabled(final Context context) {
    return getLocationManager(context).isProviderEnabled(LocationManager.GPS_PROVIDER);
}

// Returns true even if the location services are disabled. Do not use this method to detect location services are enabled.
private static boolean isPassiveProviderEnabled(final Context context) {
    return getLocationManager(context).isProviderEnabled(LocationManager.PASSIVE_PROVIDER);
}

public static boolean isLocationModeOn(final Context context) throws Exception {
    int locationMode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE);
    return locationMode != Settings.Secure.LOCATION_MODE_OFF;
}

public static boolean isLocationEnabled(final Context context) {
    try {
        return isNetworkProviderEnabled(context) || isGpsProviderEnabled(context)  || isLocationModeOn(context);
    } catch (Exception e) {
        Log.e(TAG, "[isLocationEnabled] error:", e);
    }
    return false;
}

public static void gotoLocationSettings(final Activity activity, final int requestCode) {
    Intent intent = new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS);
    activity.startActivityForResult(intent, requestCode);
}

public static String getEnabledProvidersLogMessage(final Context context){
    try{
        return "[getEnabledProvidersLogMessage] isNetworkProviderEnabled:"+isNetworkProviderEnabled(context) +
                ", isGpsProviderEnabled:" + isGpsProviderEnabled(context) +
                ", isLocationModeOn:" + isLocationModeOn(context) +
                ", isPassiveProviderEnabled(ignored):" + isPassiveProviderEnabled(context);
    }catch (Exception e){
        Log.e(TAG, "[getEnabledProvidersLogMessage] error:", e);
        return "provider error";
    }
}

}

使用 isLocationEnabled 方法检测位置服务是否启用。

https://github.com/Polidea/RxAndroidBle/issues/327#页面将提供更多信息，为什么不使用被动提供程序，而是使用位置模式。

于 2020-04-17T08:44:39.280 回答
2

您可以请求位置更新并一起显示对话框，就像 GoogleMaps 一样。这是代码：

googleApiClient = new GoogleApiClient.Builder(getActivity())
                .addApi(LocationServices.API)
                .addConnectionCallbacks(this)
                .addOnConnectionFailedListener(this).build();
googleApiClient.connect();

LocationRequest locationRequest = LocationRequest.create();
locationRequest.setPriority(LocationRequest.PRIORITY_HIGH_ACCURACY);
locationRequest.setInterval(30 * 1000);
locationRequest.setFastestInterval(5 * 1000);
LocationSettingsRequest.Builder builder = new LocationSettingsRequest.Builder()
                    .addLocationRequest(locationRequest);

builder.setAlwaysShow(true); //this is the key ingredient

PendingResult<LocationSettingsResult> result = LocationServices.SettingsApi.checkLocationSettings(googleApiClient, builder.build());
result.setResultCallback(new ResultCallback<LocationSettingsResult>() {
    @Override
    public void onResult(LocationSettingsResult result) {
        final Status status = result.getStatus();
        final LocationSettingsStates state = result.getLocationSettingsStates();
        switch (status.getStatusCode()) {
            case LocationSettingsStatusCodes.SUCCESS:
                // All location settings are satisfied. The client can initialize location
                // requests here.
                break;
            case LocationSettingsStatusCodes.RESOLUTION_REQUIRED:
                // Location settings are not satisfied. But could be fixed by showing the user
                // a dialog.
                try {
                    // Show the dialog by calling startResolutionForResult(),
                    // and check the result in onActivityResult().
                    status.startResolutionForResult(getActivity(), 1000);
                } catch (IntentSender.SendIntentException ignored) {}
                break;
            case LocationSettingsStatusCodes.SETTINGS_CHANGE_UNAVAILABLE:
                // Location settings are not satisfied. However, we have no way to fix the
                // settings so we won't show the dialog.
                break;
            }
        }
    });
}

如果您需要更多信息，请查看LocationRequest类。

于 2016-04-04T15:22:38.027 回答
1

如果您使用的是 AndroidX，请使用以下代码检查位置服务是否启用：

fun isNetworkServiceEnabled(context: Context) = LocationManagerCompat.isLocationEnabled(context.getSystemService(LocationManager::class.java))
于 2019-12-31T18:49:55.033 回答
0

要检查网络提供商，您只需将传递给 isProviderEnabled 的字符串更改为 LocationManager.NETWORK_PROVIDER 如果您检查 GPS 提供商和网络提供商的返回值 - 两者都为 false 表示没有位置服务

于 2012-11-22T16:48:09.893 回答
0 
    LocationManager lm = (LocationManager)this.getSystemService(Context.LOCATION_SERVICE);
    boolean gps_enabled = false;
    boolean network_enabled = false;

    try {
        gps_enabled = lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
    } catch(Exception e){
         e.printStackTrace();
    }

    try {
        network_enabled = lm.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
    } catch(Exception e){
         e.printStackTrace();
    }

    if(!gps_enabled && !network_enabled) {
        // notify user
        new AlertDialog.Builder(this)
                .setMessage("Please turn on Location to continue")
                .setPositiveButton("Open Location Settings", new DialogInterface.OnClickListener() {
                    @Override
                    public void onClick(DialogInterface paramDialogInterface, int paramInt) {
                        startActivity(new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS));
                    }

                }).
                setNegativeButton("Cancel",null)
                .show();
    }
于 2020-01-28T16:39:58.173 回答