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#Lab 7-3 The Dice Game
#add libraries needed
import random

#the main function
def main():
    print

    #initiliaze variables
    endProgram = 'no'
    playerOne = 'NO NAME'
    playerTwo = 'NO NAME'

    #call to inputNames
    playerOne, playerTwo = inputNames(playerOne, playerTwo)

    #while loop to run program again
    while endProgram == 'no':
        winnersName = 'NO NAME'
        p1number = 0
        p2number = 0

        #initiliaze variables

        #call to rollDice
        winnerName = rollDice(playerOne, playerTwo, winnerName)

        #call to displayInfo
        winnerName = displayInfo (winnerName)

        endProgram = input('Do you want to end program?(Enter yes or no): ')

#this function gets players names
def inputNames():
    inputNames = string('Enter your names: ')
    return playerOne, playerTwo    

#this function will get the random values
def rollDice():
    p1number = random.randint(1,6)
    p2number = random.randint(1,6)
    if p1number >= p2number:
        winnerName = playerOne
    if p1number == p2numer:
        winnerName = 'TIE'
    elif winnerName == playerTwo:
        return winnerName

#this function displays the winner
def displayInfo():
    print ('The winner is: ', winnerName)


#calls main
main()

初学者程序员在这里并试图完成一项任务。第 19 行返回错误：TypeError: inputNames() 不接受任何参数（给定 2）。第 19 行：playerOne, playerTwo = inputNames(playerOne, playerTwo)。这条线是我的教授提供的，我不知道如何让它工作。任何帮助将不胜感激！

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1 回答 1

3

函数 inputNames 被定义为一个不带参数的函数，但是您在方法列表中传递了两个变量：

这是您定义它的方式：

def inputNames():
    inputNames = string('Enter your names: ')
    return playerOne, playerTwo

你是这样称呼它的：

playerOne, playerTwo = inputNames(playerOne, playerTwo)

你真正想要的是这个函数返回玩家一和玩家二的名字。所以上面的行应该是：

playerOne, playerTwo = inputNames()

并且该函数必须在本地收集这两个名称并返回它们，可能是这样的：

def inputNames():
    p1 = str(raw_input("Enter the name for player one: "))
    p2 = str(raw_input("Enter the name for player two: "))
    return p1, p2
于 2012-04-24T19:40:50.253 回答