1

我之前有一个 FileUpload 控件,可以将每个文件单独上传到数据库中。但现在我希望能够批量上传。

我的要求是 csv 文件包含文件名和文件路径,我需要使用 FileUpload 上传 csv 并最终运行读取 csv 并将每个文件插入表申请人附件的代码。ApplyAttachment 具有列文件名 (NVARCHAR)、文件路径 (NVARCHAR)、附件 (VARBINARY)。在这个附件列中,我需要保存 csv 中提到的文件的二进制格式。我的 CSV 看起来像这样 FileName FilePath dl-54a.pdf c:\users\abc\desktop\dl-54a.pdf xyz.doc c:\users\abc\desktop\xyz.doc

我希望我能做这样的事情。但我知道我们不能将文件名等分配给 Fileupload 对象。任何的意见都将会有帮助。

    <asp:FileUpload ID="csvFile" runat="server" Width="400" /></td>
    <asp:Button ID="btnUpload" Text="Upload" runat="server" OnClick="btnUpload_Click" /></td>
    protected void btnUpload_Click(object sender, EventArgs e)
    {
        if (csvFile.HasFile)
        {
            List<string[]> filesToUpload = parseCSV(csvFile.PostedFile.FileName);
            SaveFiles(filesToUpload);
        }
    }

    public List<string[]> parseCSV(string path)
    {
        List<string[]> parsedData = new List<string[]>();
        try
        {
            using (StreamReader readFile = new StreamReader(path))
            {
                string line;
                string[] row;

                while ((line = readFile.ReadLine()) != null)
                {
                    if (!readFile.ReadLine().Contains("ApplicantId"))
                    {
                        row = line.Split(',');                            
                        parsedData.Add(row);
                    }
                }
            }
        }
        catch (Exception e)
        {
            ;
        }

        return parsedData;
    }

    private void SaveFiles(List<string[]> files)
    {
        foreach (string[] attachment in files)
        {
            using (DataClasses1DataContext db = new DataClasses1DataContext())
            {
                FileUpload fu = new FileUpload();
                fu.FileName = attachment[1].ToString();
                if (fu.HasFile)
                {
                    ApplicantAttachment aa1 = new ApplicantAttachment();
                    aa1.Filename = attachment[0].ToString();
                    aa1.FileType = fu.PostedFile.ContentType;
                    aa1.Attachment = fu.FileBytes;
                    db.ApplicantAttachments.InsertOnSubmit(aa1);
                    db.SubmitChanges();
                }
            }
        }
    }
4

1 回答 1

0

这是有效的。无法使用文件上传。

     private void SaveFiles(List<string[]> files)
     {
        foreach (string[] attachment in files)
        {
            using (DataClasses1DataContext db = new DataClasses1DataContext())
            {
                string path = attachment[1].ToString();
                byte[] fileBytes = File.ReadAllBytes(path);

                ApplicantAttachment aa1 = new ApplicantAttachment();
                aa1.Filename = attachment[0].ToString();
                aa1.FileType = MIMEType.GetType(attachment[1].ToString());
                aa1.Attachment = fileBytes;
                db.ApplicantAttachments.InsertOnSubmit(aa1);
                db.SubmitChanges();

            }
        }
     }
于 2012-04-25T16:25:48.157 回答