我需要这样的东西
SELECT CLIENT_AHCCCS_ID + CLIENT_FIRST_NAME + CLIENT_LAST_NAME + replace(convert(datetime, DATE_OF_BIRTH, 1), '/', '')
FROM tblCLIENT
WHERE CLIENT_AHCCCS_ID IS NOT NULL AND CLIENT_AHCCCS_ID LIKE 'A%'
但必须确保
CLIENT_AHCCCS_ID ( 9 character )
Member Last Name ( 25 character )
First Name ( 25 character )
我必须使用空格来填充字符串。我怎么能做到这一点?