11

当我运行以下 servlet 时：

// package projectcodes;
public void doPost(HttpServletRequest request,HttpServletResponse response) throws ServletException,IOException {
    String UserID = request.getParameter("UserID");
    String UserPassword = request.getParameter("UserPassword");
    String userName = null;
    String Email = null;
    Encrypter encrypter = new Encrypter();
    String hashedPassword = null;
    try {
        hashedPassword = encrypter.hashPassword(UserPassword);
        Context context = new InitialContext();
        DataSource ds = (DataSource)context.lookup("java:comp/env/jdbc/photog");
        Connection connection = ds.getConnection();
        String sqlStatement = "SELECT email,firstname FROM registrationinformation WHERE password='" + hashedPassword + "'";
        PreparedStatement statement = connection.prepareStatement(sqlStatement);
        ResultSet set = statement.executeQuery();
        userName = set.getString(1);  // <<---------- Line number 28
        response.sendRedirect("portfolio_one.jsp");
        // userName = set.getString("FirstName");
        Email = set.getString(3);
        if(set.wasNull() || Email.compareTo(UserID) != 0) {
            // turn to the error page
            response.sendRedirect("LoginFailure.jsp");
        } else {
            // start the session and take to his homepage
            HttpSession session = request.getSession();
            session.setAttribute("UserName", userName);
            session.setMaxInactiveInterval(900); // If the request doesn't come withing 900 seconds the server will invalidate the session
            RequestDispatcher rd = request.getRequestDispatcher("portfolio_one.jsp");
            rd.forward(request, response); // forward to the user home-page
        }
    }catch(Exception exc) {
        System.out.println(exc);
    }

我得到以下异常：

INFO: java.sql.SQLException: Invalid operation at current cursor position.
at org.apache.derby.client.am.SQLExceptionFactory40.getSQLException(Unknown Source)
at org.apache.derby.client.am.SqlException.getSQLException(Unknown Source)
at org.apache.derby.client.am.ResultSet.getString(Unknown Source)
at com.sun.gjc.spi.base.ResultSetWrapper.getString(ResultSetWrapper.java:155)

-----> at projectcodes.ValidateDataForSignIn.doPost(ValidateDataForSignIn.java:28

at javax.servlet.http.HttpServlet.service(HttpServlet.java:754)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:847)
at org.apache.catalina.core.StandardWrapper.service(StandardWrapper.java:1539)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:281)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:175)
at org.apache.catalina.core.StandardPipeline.doInvoke(StandardPipeline.java:655)
at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:595)
at com.sun.enterprise.web.WebPipeline.invoke(WebPipeline.java:98)
at com.sun.enterprise.web.PESessionLockingStandardPipeline.invoke(PESessionLockingStandardPipeline.java:91)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:162)
at org.apache.catalina.connector.CoyoteAdapter.doService(CoyoteAdapter.java:330)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:231)
at com.sun.enterprise.v3.services.impl.ContainerMapper.service(ContainerMapper.java:174)
at com.sun.grizzly.http.ProcessorTask.invokeAdapter(ProcessorTask.java:828)
at com.sun.grizzly.http.ProcessorTask.doProcess(ProcessorTask.java:725)
at com.sun.grizzly.http.ProcessorTask.process(ProcessorTask.java:1019)
at com.sun.grizzly.http.DefaultProtocolFilter.execute(DefaultProtocolFilter.java:225)
at com.sun.grizzly.DefaultProtocolChain.executeProtocolFilter(DefaultProtocolChain.java:137)
at com.sun.grizzly.DefaultProtocolChain.execute(DefaultProtocolChain.java:104)
at com.sun.grizzly.DefaultProtocolChain.execute(DefaultProtocolChain.java:90)
at com.sun.grizzly.http.HttpProtocolChain.execute(HttpProtocolChain.java:79)
at com.sun.grizzly.ProtocolChainContextTask.doCall(ProtocolChainContextTask.java:54)
at com.sun.grizzly.SelectionKeyContextTask.call(SelectionKeyContextTask.java:59)
at com.sun.grizzly.ContextTask.run(ContextTask.java:71)
at com.sun.grizzly.util.AbstractThreadPool$Worker.doWork(AbstractThreadPool.java:532)
at com.sun.grizzly.util.AbstractThreadPool$Worker.run(AbstractThreadPool.java:513)
at java.lang.Thread.run(Thread.java:722)
    Caused by: org.apache.derby.client.am.SqlException: Invalid operation at current cursor position.
at org.apache.derby.client.am.ResultSet.checkForValidCursorPosition(Unknown Source)
at org.apache.derby.client.am.ResultSet.checkGetterPreconditions(Unknown Source)
... 30 more

上面来自服务器的日志显示第 28 行是异常的原因。但我无法得到异常的原因。表中的所有列都具有 varchar 数据类型。

我在 servlet 代码中突出显示了第 28 行（根据服务器日志导致异常的原因） 。

4

5 回答 5

38

您应该next首先使用该语句。

ResultSet set = statement.executeQuery();
if (set.next()) {
    userName = set.getString(1);
    //your logic...
}

更新

正如 Java 6 文档所说

ResultSet 游标最初位于第一行之前；第一次调用 next 方法使第一行成为当前行；第二次调用使第二行成为当前行，依此类推。

这意味着当你执行句子时

ResultSet set = statement.executeQuery();

ResultSetset将被创建并指向数据的第一个结果之前的一行。你可以这样看：

从注册信息中选择电子邮件、名字

    email              | firstname
    ____________________________________
0                                        <= set points to here
1   email1@gmail.com   | Email1 Person
2   foo@bar.com        | Foo Bar

因此，在打开您的 ResulSet 之后，您执行该方法next将其移动到第一行。

if(set.next())

现在set看起来像这样。

    email              | firstname
    ____________________________________
0
1   email1@gmail.com   | Email1 Person   <= set points to here
2   foo@bar.com        | Foo Bar

如果你需要读取 ResultSet 中的所有数据，你应该使用 while 而不是 if：

while(set.next()) {
    //read data from the actual row
    //automatically will try to forward 1 row
}

如果set.next()返回 false，则意味着没有要读取的行，因此您的 while 循环将结束。

更多信息在这里。

于 2012-04-24T13:27:57.780 回答
1

您必须将指针设置到正确的位置：

while(set.hasNext()){
    set.next();
    String a = set.getString(1);
    String b = set.getString(2);
}
于 2012-04-24T13:28:52.283 回答
1

结果集集 = statement.executeQuery();

迭代集合，然后获取字符串。

        while(set.next()) {
me = set.getString(1);  // <<---------- Line number 28

}
于 2012-04-24T13:29:12.507 回答
1

初始化 ResultSet 后检查游标中是否有行，例如

if(rs.next()){ //your all other works should go here }

于 2018-01-22T11:20:49.190 回答
0

您可以通过以下方式获得第一个：rs.first()

于 2018-12-18T05:58:34.263 回答