我正在编写一个带有身份验证的简单 smtp 发件人。这是我的代码
SMTPserver, sender, destination = 'smtp.googlemail.com', 'user@gmail.com', ['reciever@gmail.com']
USERNAME, PASSWORD = "user", "password"
# typical values for text_subtype are plain, html, xml
text_subtype = 'plain'
content="""
Hello, world!
"""
subject="Message Subject"
from smtplib import SMTP_SSL as SMTP # this invokes the secure SMTP protocol (port 465, uses SSL)
# from smtplib import SMTP # use this for standard SMTP protocol (port 25, no encryption)
from email.MIMEText import MIMEText
try:
msg = MIMEText(content, text_subtype)
msg['Subject']= subject
msg['From'] = sender # some SMTP servers will do this automatically, not all
conn = SMTP(SMTPserver)
conn.set_debuglevel(False)
conn.login(USERNAME, PASSWORD)
try:
conn.sendmail(sender, destination, msg.as_string())
finally:
conn.close()
except Exception, exc:
sys.exit( "mail failed; %s" % str(exc) ) # give a error message
它工作完美,直到我尝试发送非 ascii 符号(俄语西里尔文)。我应该如何在消息中定义字符集以使其以正确的方式显示?提前致谢!
UPD。我改变了我的代码:
text_subtype = 'text'
content="<p>Текст письма</p>"
msg = MIMEText(content, text_subtype)
msg['From']=sender # some SMTP servers will do this automatically, not all
msg['MIME-Version']="1.0"
msg['Subject']="=?UTF-8?Q?Тема письма?="
msg['Content-Type'] = "text/html; charset=utf-8"
msg['Content-Transfer-Encoding'] = "quoted-printable"
…
conn.sendmail(sender, destination, str(msg))
所以,我第一次指定 text_subtype = 'text',然后在标题中放置一个 msg['Content-Type'] = "text/html; charset=utf-8" 字符串。这是正确的吗?
更新最后,我解决了我的消息问题你应该像 msg = MIMEText(content.encode('utf-8'), 'plain', 'UTF-8') 这样写