java - 如何选择条件等于 null 的位置。

Question

SQL 语句：

select * FROM Message
 WHERE senderId = 126 and receiverId = 125
   and dateReceived is null

HQL 语句：

 FROM Message
WHERE senderId = :senderId and receiverId = :receiverId
 and dateReceived is null

我有错误。那么如何编写 HQL 以获得与上述 sql 语句相同的结果呢？

Answer 1

尝试使用 IS EMPTY 应该可以。

Answer 2

senderId 和receiverId 是外键吗？如果是，那么假设 senderId 是 Sender 表的一列，receiverId 是 Receiver 表的一列，试试这个：

select msg FROM Message msg
 WHERE msg.Sender.senderId = 126 and msg.Receiver.receiverId = 125
   and msg.dateReceived is null

或者

Select msg FROM Message msg
WHERE msg.senderId = :senderId and msg.receiverId = :receiverId
 and msg.dateReceived is null

Answer 3

我已经解决了

HQL 查询：FROM Message WHERE senderId = :senderId 和 receiverId = :receiverId 和 dateReceived = null