unix - 是否有一些 Unix 实用程序可以让我用很少的输入来 grep 多个文件？

Question

现在我经常这样做：

find * | grep py$ | xargs grep foo

我记得有一些实用程序可以用更少的输入来做到这一点，但是哪个？

更新：如果可能，我更喜欢使用 Bash shell。

Answer 1

I love ack:

Which would you rather type?

$ grep pattern $(find . -type f | grep -v '\.svn')

$ ack pattern

Answer 2

你可能会发现你的 shell 对你有帮助。例如，在zsh中，您可以这样做

grep foo **/*.py

前提是 .py 文件的数量不超过命令允许的最大参数数量（64k？）。请注意，您可以限定文件通配符，例如

grep foo **/*.py(mh-5)

这将为您提供过去 5 小时内修改的所有内容。

Answer 3

Have you tried ack.

Answer 4

zsh 有递归通配符，所以你可以这样做

grep foo **/*.py

看马，没有找到:)

更新：哦，如果你做了很多事情，当然可以为它命名或编写一个函数

Answer 5

它被称为 grep *wink* :-)

当前目录下的所有py

grep -R foo *.py

当前和任何子目录中的所有文件

grep -R foo .

Answer 6

grep -r --include='*.py' foo *

Answer 7

find . -name "*.py" -exec grep -H foo '{}' ';'

Answer 8

I use something very much like your find/grep pair a lot, although with even more conditions -- excluding files in .svn directories, for example. I do this so much I just made scripts around these invocations, so I can call "src-grep ..." and have it do basically what you're doing here. (Then I added an optional extension for a number of context lines to pass to the grep -C flag, if supplied, and a separate version to grep the results for definition statements.)

This is more useful and faster than recursive grep for me.