21

我一直在寻找 2 天的答案，但没有任何结果。

我正在尝试在 Django 上集成 Oauth2 以使用 Google 登录。我的代码抛出异常 - “令牌无效”。

有时候是这样的：

resp, content = client.request(access_token_url, "POST")
    if resp['status'] != '200':
        print content
        raise Exception("Invalid response from Google."+content)

在 google_authenticate()

请帮我。

我的代码：

    def google_login(request):
    scope = "https://www.googleapis.com/auth/userinfo.profile"

    request_token_url = "https://www.google.com/accounts/OAuthGetRequestToken?scope=%s" % scope
    authorize_url = 'https://www.google.com/accounts/OAuthAuthorizeToken'
    authenticate_url = "https://accounts.google.com/o/oauth2/auth"

    response_type = "code"
    redirect_uri = "http://127.0.0.1:8000/login/google/auth"
    scope = "https://www.googleapis.com/auth/userinfo.profile"

    oauth_key = settings.GOOGLE_KEY
    oauth_secret = settings.GOOGLE_SECRET

    consumer = oauth.Consumer(oauth_key, oauth_secret)
    client = oauth.Client(consumer)

    # Step 1: Get a request token. This is a temporary token that is used for 
    # having the user authorize an access token and to sign the request to obtain 
    # said access token.

    resp, content = client.request(request_token_url, "POST")
    request_token = dict(urlparse.parse_qsl(content))

    if resp['status'] != '200':
        raise Exception("Invalid response from Google.")

    # Step 2. Store the request token in a session for later use.
    request.session['request_token'] = dict(cgi.parse_qsl(content))

    # Step 3. Redirect the user to the authentication URL.
    url = "%s?oauth_token=%s&client_id=%s&response_type=%s&redirect_uri=%s&scope=%s" % (authenticate_url,
        request.session['request_token']['oauth_token'],
        oauth_key,response_type,redirect_uri,scope)

    return HttpResponseRedirect(url)

def google_authenticate(request):
    access_token_url = 'https://www.google.com/accounts/OAuthGetAccessToken'

    oauth_key = settings.GOOGLE_KEY
    oauth_secret = settings.GOOGLE_SECRET

    consumer = oauth.Consumer(oauth_key, oauth_secret)

    # Step 1. Use the request token in the session to build a new client.
    token = oauth.Token(request.session['request_token']['oauth_token'],
        request.session['request_token']['oauth_token_secret'])
    if 'oauth_verifier' in request.GET:
        token.set_verifier(request.GET['oauth_verifier'])
    client = oauth.Client(consumer, token)

    # Step 2. Request the authorized access token from Google.
    resp, content = client.request(access_token_url, "POST")
    if resp['status'] != '200':
        print content
        raise Exception("Invalid response from Google."+content)

    access_token = dict(cgi.parse_qsl(content))

    # Step 3. Lookup the user or create them if they don't exist.
    try:
        user = User.objects.get(username=access_token['screen_name'])
    except User.DoesNotExist:
        # When creating the user I just use their screen_name@twitter.com
        # for their email and the oauth_token_secret for their password.
        # These two things will likely never be used. Alternatively, you 
        # can prompt them for their email here. Either way, the password 
        # should never be used.
        user = User.objects.create_user(access_token['screen_name'],
            '%s@twitter.com' % access_token['screen_name'],
            access_token['oauth_token_secret'])

        # Save our permanent token and secret for later.
        profile = Profile()
        profile.user = user
        profile.oauth_token = access_token['oauth_token']
        profile.oauth_secret = access_token['oauth_token_secret']
        profile.save()

    # Authenticate the user and log them in using Django's pre-built 
    # functions for these things.
    user = authenticate(username=access_token['screen_name'],
        password=access_token['oauth_token_secret'])
    login(request, user)

    return HttpResponseRedirect('/')
4

1 回答 1

30

经过很长一段时间，浪费了很多时间，我放弃了 OAuth2，因为它很难配置，我只需要登录一个用户。下面的代码应该可以帮助需要做类似事情的人，并且可以定制。我所做的只是按照关于形成 url 的说明进行操作 -> https://developers.google.com/accounts/docs/OAuth2Login

我创建了两个视图（对于不使用 Django 的任何人 - 页面）并链接到第一个： 这个页面我称为 login/google 并从登录页面链接到它。

def google_login(request):
    token_request_uri = "https://accounts.google.com/o/oauth2/auth"
    response_type = "code"
    client_id = XXXXXX-your_client_id
    redirect_uri = "http://mysite/login/google/auth"
    scope = "https://www.googleapis.com/auth/userinfo.profile https://www.googleapis.com/auth/userinfo.email"
    url = "{token_request_uri}?response_type={response_type}&client_id={client_id}&redirect_uri={redirect_uri}&scope={scope}".format(
        token_request_uri = token_request_uri,
        response_type = response_type,
        client_id = client_id,
        redirect_uri = redirect_uri,
        scope = scope)
    return HttpResponseRedirect(url)

上面的代码重定向到第二个页面（这个页面必须在google app定义中定义为一个redirect uri）。我将此页面称为 login/google/auth：

def google_authenticate(request):
    parser = Http()
    login_failed_url = '/'
    if 'error' in request.GET or 'code' not in request.GET:
        return HttpResponseRedirect('{loginfailed}'.format(loginfailed = login_failed_url))

    access_token_uri = 'https://accounts.google.com/o/oauth2/token'
    redirect_uri = "http://mysite/login/google/auth"
    params = urllib.urlencode({
        'code':request.GET['code'],
        'redirect_uri':redirect_uri,
        'client_id':XXXXX_your_google_key,
        'client_secret':XXXXX_your_google_secret,
        'grant_type':'authorization_code'
    })
    headers={'content-type':'application/x-www-form-urlencoded'}
    resp, content = parser.request(access_token_uri, method = 'POST', body = params, headers = headers)
    token_data = jsonDecode(content)
    resp, content = parser.request("https://www.googleapis.com/oauth2/v1/userinfo?access_token={accessToken}".format(accessToken=token_data['access_token']))
    #this gets the google profile!!
    google_profile = jsonDecode(content)
    #log the user in-->
    #HERE YOU LOG THE USER IN, OR ANYTHING ELSE YOU WANT
    #THEN REDIRECT TO PROTECTED PAGE
    return HttpResponseRedirect('/dashboard')

我真的希望这可以帮助人们，并节省我浪费的时间。非常欢迎对代码发表评论！

于 2012-05-11T06:41:20.153 回答