0

现在我有这样的控制器方法：

     def modelv
    @model = Model.find(:all, :conditions => { :MOD_MFA_ID => params[:man]}) 
    @ct = CountryDesignation.find(:all, :conditions => { :CDS_ID => "110000002"})
    @destext = DesText.find(:all, :conditions => { :TEX_ID => "388555"})
    respond_to do |format|
      format.html # show.html.erb
      format.xml  { render :xml => @model }
    end
  end

但我希望它看起来像这样：

 def modelv
    @model = Model.find(:all, :conditions => { :MOD_MFA_ID => params[:man]}) 
    @ct = CountryDesignation.find(:all, :conditions => { :CDS_ID => @model.MOD_CDS_ID})
    @destext = DesText.find(:all, :conditions => { :TEX_ID => @ct.CDS_TEX_ID})
    respond_to do |format|
      format.html # show.html.erb
      format.xml  { render :xml => @model }
    end
  end

但我的模型结构是：

COUNTRY_DESIGNATIONS has_many 型号

DES_TEXTS has_many COUNTRY_DESIGNATIONS

制造商 has_many 型号

因此，如果我选择 @model - 它是数组，如果选择 @ct - 它是数组（对于每个模型），如果选择 @destext - 它是数组。如何正确选择这个。以及如何在视图中显示它？现在我的观点是这样的：

%p#notice= notice

%h3
  - @model.each do |model| 
    %tr
      %p
        mod_id
        %td= model.MOD_ID
        name
        -#%td= model.country_designations.des_texts.TEX_TEXT
      = link_to 'Show model', model
= link_to 'Back', manufacturers_path

我不会看起来像这样：

%p#notice= notice

%h3
  - @model.each do |model| 
    %tr
      %p
        mod_id
        %td= model.MOD_ID
        name
        %td= @destext.TEX_TEXT
      = link_to 'Show model', model

= link_to 'Back', manufacturers_path
4

1 回答 1

0

如果 MODELS belongs_to COUNTRY_DESIGNATIONS 和 COUNTRY_DESIGNATIONS belongs_to DES_TEXTS 那么查找应该只返回一个结果。那你就不需要 find(:all, ...)，你需要

@model = Model.find(:first, :conditions => { :MOD_MFA_ID => params[:man]}) 
@ct = CountryDesignation.find(:first, :conditions => { :CDS_ID => "110000002"})
@destext = DesText.find(:first, :conditions => { :TEX_ID => "388555"})
于 2012-04-21T23:27:00.210 回答