c# - 将列中的 XML 转换为表

Question

我的输入是 SQL Server 表中的一个 XML 列，如下所示：

<word Entry="Ketab" Affix="miyanvand" Pos="esm" Derv="Jamed" />

期望的输出：这样的表：

Entry    | Affix       | Pos     | Derv
Ketab    | miyanvand   | esm     | Jamed

Answer 1

如果您使用的是 sql-server 2005+。然后可能是这样的：

DECLARE @xml XML=
'<word Entry="Ketab" Affix="miyanvand" Pos="esm" Derv="Jamed" />'

SELECT 
   Y.ID.value('(@Entry)[1]', 'Varchar(100)') as [Entry],
   Y.ID.value('(@Affix)[1]', 'Varchar(100)') as [Affix],
   Y.ID.value('(@Pos)[1]', 'Varchar(100)') as [Pos],
   Y.ID.value('(@Derv)[1]', 'Varchar(100)') as [Derv]
FROM @xml.nodes('/word') as Y(ID)

或者你也可以这样做：

DECLARE @xml XML=
'<word Entry="Ketab" Affix="miyanvand" Pos="esm" Derv="Jamed" />'

SELECT 
    @xml.value('(/word/@Entry)[1]', 'varchar(50)') as Entry,
    @xml.value('(/word/@Affix)[1]', 'varchar(50)') as Affix,
    @xml.value('(/word/@Pos)[1]', 'varchar(50)') as Pos,
    @xml.value('(/word/@Derv)[1]', 'varchar(50)') as Derv

或者，如果你有一张桌子。然后是这样的：

DECLARE @tbl TABLE(ID INT,someXML XML)
INSERT INTO @tbl
VALUES
    (1,'<word Entry="Ketab" Affix="miyanvand" Pos="esm" Derv="Jamed" />')

SELECT
    tbl.ID,
    Y.ID.value('(@Entry)[1]', 'Varchar(100)') as [Entry],
    Y.ID.value('(@Affix)[1]', 'Varchar(100)') as [Affix],
    Y.ID.value('(@Pos)[1]', 'Varchar(100)') as [Pos],
    Y.ID.value('(@Derv)[1]', 'Varchar(100)') as [Derv]
FROM
    @tbl AS tbl
    CROSS APPLY someXML.nodes('/word') as Y(ID)

Answer 2

您可以value在 XML 列上使用该函数：

declare @t table (col1 xml)
insert @t values ('<word Entry="Ketab" Affix="miyanvand" />')

select  t.col1.value('(/word/@Entry)[1]', 'varchar(50)') as Entry
,       t.col1.value('(/word/@Affix)[1]', 'varchar(50)') as Affix
from    @t t