1

我正在尝试用 Python 编写一个简单的“密码”程序，该程序允许 3 次尝试使用递归函数“登录”。我不知道为什么它不起作用......（是的，侏罗纪公园的灵感）

def magicWord(count):
    int(count)
    answer = raw_input("What is the password? ")
    if answer == 'lucas':
        print 'ACESS GRANTED'
    else:
        count =+ 1
        if count > 2:
            while count > 2:
                count+=1
                print "na na na you didn\'t say the magic word. "
        else:
            magicWord(count)

magicWord(0)
4

3 回答 3

2

你非常亲近。只有几个小问题：

def magicWord(count):
    answer = raw_input("What is the password? ")
    if answer == 'lucas':
        print 'ACESS GRANTED'
    else:
        count += 1
        if count > 2:
            print "na na na you didn\'t say the magic word. "
            return
        else:
            magicWord(count)

这是一个示例会话：

>>> magicWord(0)
What is the password? alan
What is the password? ellie
What is the password? ian
na na na you didn't say the magic word.
于 2012-04-21T06:09:14.413 回答
1

你真的需要递归吗？我的变种不使用它，它似乎更容易

def magic_word(attempts):
   for attempt in range(attempts):
      answer = raw_input("What is the password? ")
      if answer == 'lucas':
          return True
   return False

if magic_word(3):
   print 'ACESS GRANTED'
else:
   print "na na na you didn\'t say the magic word. "
于 2012-04-21T06:07:24.220 回答
1

干得好！没有硬编码函数内尝试次数的递归：

def magicword(attempts):
    valid_pw = ['lucas']
    if attempts:
        answer = raw_input('What is the password?')
        if answer in valid_pw:
            return True
        else:
            return magicword(attempts -1)

if magicword(3):
    print 'you got it right'
else:
    print "na na na you didn't say the magic word"

返回：

What is the password?ian
What is the password?elli
What is the password?bob
na na na you didn't say the magic word
>>> ================================ RESTART ================================
>>> 
What is the password?ian
What is the password?lucas
you got it right
于 2012-04-21T06:39:39.577 回答