Android - 我想从用户那里得到一个数字输入到 EditText - 它需要用空格分隔 - 每 4 个字符。示例：123456781234 -> 1234 5678 1234
这仅用于视觉目的。但是我需要没有空格的字符串以供进一步使用。
我能做到这一点的最简单方法是什么？
问问题
31080 次
14 回答
14
这是信用卡的编辑文本吗？
首先创建计数变量
int count = 0;
然后把它放在你的 oncreate(activity) / onviewcreated(fragment)
ccEditText.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start,
int count, int after) { /*Empty*/}
@Override
public void onTextChanged(CharSequence s, int start, int before,
int count) { /*Empty*/ }
@Override
public void afterTextChanged(Editable s) {
int inputlength = ccEditText.getText().toString().length();
if (count <= inputlength && inputlength == 4 ||
inputlength == 9 || inputlength == 14)){
ccEditText.setText(ccEditText.getText().toString() + " ");
int pos = ccEditText.getText().length();
ccEditText.setSelection(pos);
} else if (count >= inputlength && (inputlength == 4 ||
inputlength == 9 || inputlength == 14)) {
ccEditText.setText(ccEditText.getText().toString()
.substring(0, ccEditText.getText()
.toString().length() - 1));
int pos = ccEditText.getText().length();
ccEditText.setSelection(pos);
}
count = ccEditText.getText().toString().length();
}
});
于 2016-05-01T16:17:15.677 回答
12
正如@waqas 指出的那样，如果您的目标是在用户键入数字时实现这一点，则需要使用 TextWatcher。这是实现空间的一种潜在方法：
StringBuilder s;
s = new StringBuilder(yourTxtView.getText().toString());
for(int i = 4; i < s.length(); i += 5){
s.insert(i, " ");
}
yourTxtView.setText(s.toString());
每当您需要获取不带空格的字符串时，请执行以下操作：
String str = yourTxtView.getText().toString().replace(" ", "");
于 2012-04-20T20:09:10.367 回答
8
有一种更简单的方法可以实现这一点：
editText.doAfterTextChanged { text ->
val formattedText = text.toString().replace(" ", "").chunked(4).joinToString(" ")
if (formattedText != text.toString()) {
editText.setText(formattedText)
}
}
当您想获得没有空格的文本时，只需执行以下操作：
editText.text.toString().replace(" ","")
于 2021-03-29T14:31:57.457 回答
4
您需要使用TextWatcher来实现视觉目的空间。
并使用任何按空间逻辑简单拆分的字符串将其加入或循环遍历每个字符的整个字符串并(char) 32从字符串中消除
于 2012-04-20T20:01:23.483 回答
3
我创建了一个封装给定行为的类。
/**
* Custom [TextWatcher] class that appends a given [separator] for every [interval].
*/
abstract class SeparatorTextWatcher(
private val separator: Char,
private val interval: Int
) : TextWatcher {
private var dirty = false
private var isDelete = false
override fun afterTextChanged(editable: Editable?) {
if (dirty) return
dirty = true
val text = editable.toString().handleSeparator()
onAfterTextChanged(text)
dirty = false
}
override fun beforeTextChanged(s: CharSequence?, start: Int, count: Int, after: Int) {
// Empty
}
override fun onTextChanged(s: CharSequence?, start: Int, before: Int, count: Int) {
isDelete = before != 0
}
private fun String.handleSeparator(): String {
val stringBuilder = StringBuilder(this)
if (length > 0 && length.rem(interval + 1) == 0) {
if (isDelete) {
stringBuilder.deleteCharAt(length - 1)
} else {
stringBuilder.insert(length - 1, separator)
}
}
return stringBuilder.toString()
}
/**
* Subclasses must implement this method to get the formatted text.
*/
abstract fun onAfterTextChanged(text: String)
}
这是有关如何使用它的片段：
editText.addTextChangedListener(object : SeparatorTextWatcher(' ', 4) {
override fun onAfterTextChanged(text: String) {
editText.run {
setText(text)
setSelection(text.length)
}
}
})
于 2019-09-13T16:33:59.603 回答
1
我在这里搜索了很多是 kotlin 中用于卡的完整代码
yourEditText.addTextChangedListener(object : TextWatcher {
private val TOTAL_SYMBOLS = 19 // size of pattern 0000-0000-0000-0000
private val TOTAL_DIGITS = 16 // max numbers of digits in pattern: 0000 x 4
private val DIVIDER_MODULO =
5 // means divider position is every 5th symbol beginning with 1
private val DIVIDER_POSITION =
DIVIDER_MODULO - 1 // means divider position is every 4th symbol beginning with 0
private val DIVIDER = ' '
override fun beforeTextChanged(
s: CharSequence,
start: Int,
count: Int,
after: Int
) { // noop
}
override fun onTextChanged(
s: CharSequence,
start: Int,
before: Int,
count: Int
) { // noop
}
override fun afterTextChanged(s: Editable) {
if (!isInputCorrect(s, TOTAL_SYMBOLS, DIVIDER_MODULO, DIVIDER)) {
var repl = buildCorrectString(
getDigitArray(s, TOTAL_DIGITS),
DIVIDER_POSITION,
DIVIDER
)
yourEditText.clearFocus();
yourEditText.setText(repl);
yourEditText.requestFocus();
yourEditText.setSelection(repl!!.length);
}
}
private fun isInputCorrect(
s: Editable,
totalSymbols: Int,
dividerModulo: Int,
divider: Char
): Boolean {
var isCorrect =
s.length <= totalSymbols // check size of entered string
for (i in 0 until s.length) { // check that every element is right
isCorrect = if (i > 0 && (i + 1) % dividerModulo == 0) {
isCorrect and (divider == s[i])
} else {
isCorrect and Character.isDigit(s[i])
}
}
return isCorrect
}
private fun buildCorrectString(
digits: CharArray,
dividerPosition: Int,
divider: Char
): String? {
val formatted = StringBuilder()
for (i in digits.indices) {
if (digits[i] != '\u0000') {
formatted.append(digits[i])
if (i > 0 && i < digits.size - 1 && (i + 1) % dividerPosition == 0) {
formatted.append(divider)
}
}
}
return formatted.toString()
}
private fun getDigitArray(s: Editable, size: Int): CharArray {
val digits = CharArray(size)
var index = 0
var i = 0
while (i < s.length && index < size) {
val current = s[i]
if (Character.isDigit(current)) {
digits[index] = current
index++
}
i++
}
return digits
}
})
}
于 2020-07-13T15:17:32.150 回答
1
文本格式为 000 000 0000
android edittext textwatcher 格式电话号码，如 xxx-xxx-xx-xx
public class PhoneNumberTextWatcher implements TextWatcher {
private static final String TAG = PhoneNumberTextWatcher.class
.getSimpleName();
private EditText edTxt;
private boolean isDelete;
public PhoneNumberTextWatcher(EditText edTxtPhone) {
this.edTxt = edTxtPhone;
edTxt.setOnKeyListener(new View.OnKeyListener() {
@Override
public boolean onKey(View v, int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_DEL) {
isDelete = true;
}
return false;
}
});
}
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
public void beforeTextChanged(CharSequence s, int start, int count,
int after) {
}
public void afterTextChanged(Editable s) {
if (isDelete) {
isDelete = false;
return;
}
String val = s.toString();
String a = "";
String b = "";
String c = "";
if (val != null && val.length() > 0) {
val = val.replace(" ", "");
if (val.length() >= 3) {
a = val.substring(0, 3);
} else if (val.length() < 3) {
a = val.substring(0, val.length());
}
if (val.length() >= 6) {
b = val.substring(3, 6);
c = val.substring(6, val.length());
} else if (val.length() > 3 && val.length() < 6) {
b = val.substring(3, val.length());
}
StringBuffer stringBuffer = new StringBuffer();
if (a != null && a.length() > 0) {
stringBuffer.append(a);
if (a.length() == 3) {
stringBuffer.append(" ");
}
}
if (b != null && b.length() > 0) {
stringBuffer.append(b);
if (b.length() == 3) {
stringBuffer.append(" ");
}
}
if (c != null && c.length() > 0) {
stringBuffer.append(c);
}
edTxt.removeTextChangedListener(this);
edTxt.setText(stringBuffer.toString());
edTxt.setSelection(edTxt.getText().toString().length());
edTxt.addTextChangedListener(this);
} else {
edTxt.removeTextChangedListener(this);
edTxt.setText("");
edTxt.addTextChangedListener(this);
}
}
}
于 2017-07-13T09:21:14.963 回答
1
遵循 DRY 原则的@Ario 答案的更清洁版本：
private int prevCount = 0;
private boolean isAtSpaceDelimiter(int currCount) {
return currCount == 4 || currCount == 9 || currCount == 14;
}
private boolean shouldIncrementOrDecrement(int currCount, boolean shouldIncrement) {
if (shouldIncrement) {
return prevCount <= currCount && isAtSpaceDelimiter(currCount);
} else {
return prevCount > currCount && isAtSpaceDelimiter(currCount);
}
}
private void appendOrStrip(String field, boolean shouldAppend) {
StringBuilder sb = new StringBuilder(field);
if (shouldAppend) {
sb.append(" ");
} else {
sb.setLength(sb.length() - 1);
}
cardNumber.setText(sb.toString());
cardNumber.setSelection(sb.length());
}
ccEditText.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
@Override
public void afterTextChanged(Editable s) {
String field = editable.toString();
int currCount = field.length();
if (shouldIncrementOrDecrement(currCount, true)){
appendOrStrip(field, true);
} else if (shouldIncrementOrDecrement(currCount, false)) {
appendOrStrip(field, false);
}
prevCount = cardNumber.getText().toString().length();
}
});
于 2017-08-22T23:36:46.523 回答
0
这是一个小帮助功能。对于您的示例，您可以使用
addPadding(" ", "123456781234", 4);
/**
* @brief Insert arbitrary string at regular interval into another string
*
* @param t String to insert every 'num' characters
* @param s String to format
* @param num Group size
* @return
*/
private String addPadding(String t, String s, int num) {
StringBuilder retVal;
if (null == s || 0 >= num) {
throw new IllegalArgumentException("Don't be silly");
}
if (s.length() <= num) {
//String to small, do nothing
return s;
}
retVal = new StringBuilder(s);
for(int i = retVal.length(); i > 0; i -= num){
retVal.insert(i, t);
}
return retVal.toString();
}
于 2013-03-25T13:53:45.510 回答
0
如果有人仍在寻找答案，请检查格式编辑文本库
public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
final FormatEditText editText1 = findViewById(R.id.edit_text_1);
editText1.setFormat("---- ---- ---- ----");
}
}
于 2020-06-22T16:19:07.837 回答
0
如果您使用数据绑定添加
android:afterTextChanged="@{handler::afterTextChanged}"
在 EditText 和 afterTextChanged 函数中如下：
fun afterTextChanged(s: Editable) {
if (s.length > 0 && s.length % 5 === 0) {
val c: Char = s.get(s.length - 1)
if (space === c) {
s.delete(s.length - 1, s.length)
}
}
// Insert char where needed.
if (s.length > 0 && s.length % 5 === 0) {
val c: Char = s.get(s.length - 1)
// Only if its a digit where there should be a space we insert a space
if (Character.isDigit(c) && TextUtils.split(
s.toString(),
space.toString()
).size <= 3
) {
s.insert(s.length - 1, space.toString())
}
}
}
像这样添加空间
private val space: Char = ' '
如果您使用 inputType="numberDigit" 这将禁用 '-' 和 ' ' 字符，所以我建议使用 inputType="phone"
于 2021-02-14T07:14:22.943 回答
0
在打字时更改实时文本有些困难。我们应该处理以下问题。
一个。光标位置 b. 我们应该允许用户删除输入的文本。
以下代码处理这两个问题。
将 TextWatcher 添加到 EditText，并从“afterTextchanged()”获取文本并编写您的逻辑
字符串 str=""; int strOldlen=0;
@Override public void afterTextChanged(Editable s) { str = edtAadharNumber.getText().toString(); int strLen = str.length(); if(strOldlen<strLen) { if (strLen > 0) { if (strLen == 4 || strLen == 9) { str=str+" "; edtAadharNumber.setText(str); edtAadharNumber.setSelection(edtAadharNumber.getText().length()); }else{ if(strLen==5){ if(!str.contains(" ")){ String tempStr=str.substring(0,strLen-1); tempStr +=" "+str.substring(strLen-1,strLen); edtAadharNumber.setText(tempStr); edtAadharNumber.setSelection(edtAadharNumber.getText().length()); } } if(strLen==10){ if(str.lastIndexOf(" ")!=9){ String tempStr=str.substring(0,strLen-1); tempStr +=" "+str.substring(strLen-1,strLen); edtAadharNumber.setText(tempStr); edtAadharNumber.setSelection(edtAadharNumber.getText().length()); } } strOldlen = strLen; } }else{ return; } }else{ strOldlen = strLen; Log.i("MainActivity ","keyDel is Pressed ::: strLen : "+strLen+"\n old Str Len : "+strOldlen); } } }在这里，我尝试为每四个字符添加空间。添加第一个空格后，文本的长度为 5。所以下一个空格是在 9 个字符之后。
如果 (strLen== 4||strLen==9)
- 这里的另一个问题是光标位置，一旦你修改了edittext的文本，光标就会移动到第一位。所以我们需要手动设置光标。
edtAadharNumber.setSelection(edtAadharNumber.getText().length());
- 我的文本长度只有 12 个字符。所以我在做手动计算，如果你的文本是动态的，那么你编写动态逻辑。
于 2016-06-09T05:12:44.807 回答
-1
简单的答案
YourEditText.addTextChangedListener(new TextWatcher() {
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
int len=s.toString().length();
if (before == 0 && (len == 4 || len == 9 || len == 14 ))
YourEditText.append(" ");
}
@Override
public void afterTextChanged(Editable s) {
}
});
于 2019-02-18T12:09:58.587 回答
-1
假设您知道字符串的最终长度，您可以这样实现TextWatcher：
override fun setUp(view: View?) {
editText.addTextChangedListener(object : TextWatcher{
override fun beforeTextChanged(p0: CharSequence?, p1: Int, p2: Int, p3: Int) {
}
override fun onTextChanged(p0: CharSequence, p1: Int, p2: Int, p3: Int) {
if(p2 == 0 && (p0.length == 4 || p0.length == 9 || p0.length == 14))
editText.append(" ")
}
override fun afterTextChanged(p0: Editable?) {
}
})
您只需在每个 4 位数字块中添加一个空格。p2 == 0是为了保证用户不会删除，否则他/她会得到库存。
代码在 Kotlin 中，您可以在 Java 中以完全相同的方式进行操作。
于 2017-10-31T15:49:24.590 回答