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如何以编程方式在 macOS Cocoa 应用程序中创建和定位按钮？

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2 回答 2

19

定位按钮 您需要更改按钮的原点 x 和 y。查看我在下面编写的示例代码和注释。

你可以这样做：

-(void)awakeFromNib {

    //Start from bottom left corner

    int x = 100; //possition x
    int y = 100; //possition y

    int width = 130;
    int height = 40; 

    NSButton *myButton = [[[NSButton alloc] initWithFrame:NSMakeRect(x, y, width, height)] autorelease];
    [[windowOutlet contentView] addSubview: myButton];
    [myButton setTitle: @"Button title!"];
    [myButton setButtonType:NSMomentaryLightButton]; //Set what type button You want
    [myButton setBezelStyle:NSRoundedBezelStyle]; //Set what style You want

    [myButton setTarget:self];
    [myButton setAction:@selector(buttonPressed)];
}

-(void)buttonPressed {
    NSLog(@"Button pressed!"); 

    //Do what You want here...  
}

** WindowOutlet是窗口所以不要忘记 IBOutlet 它。

于 2012-04-20T19:48:55.977 回答
0

所有按钮都是控件，所有控件都是视图，因此请按顺序查看：

于 2012-04-20T19:36:23.050 回答