1

由于永远不会在 a 上触发 onClick 事件ViewPager（请参阅此问题），我将onClickListener在适配器中将 设置为项目容器。

这个想法是，当单击一个项目时，从适配器调用来自该适配器设置为的 Fragment 的方法ViewPager。

对于一个Activity我会传递上下文并使用这个上下文调用方法（类似于((myActivity)context).itemContainerOnClick()）。

但是我该如何处理片段？将 Fragment 作为参数传递给适配器的构造函数时，我会遇到任何问题吗？

谢谢

分段

public class MyFragment extends Fragment {

    ViewPager mViewPager;

    int mPosition = 0;

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
            Bundle savedInstanceState) {

        view = (RelativeLayout) inflater.inflate(R.layout.my_fragment_container, container, false);

        ViewPager viewPager = (ViewPager) view.findViewById(R.id.viewpager);

        mViewPager.setAdapter(new MyAdapter(getActivity(), myObjectArray);

        mViewPager.setOnPageChangeListener(new OnPageChangeListener() {

            @Override
            public void onPageSelected(int position) {
                mPosition = position;
            }

            @Override
            public void onPageScrolled(int position, float positionOffset, int positionOffsetPixels) {}

            @Override
            public void onPageScrollStateChanged(int state) {}
        });

        mViewPager.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View v) {
                // I want to start some activity, passing mPosition
                // but this is never called
            }
        }); 


        return view;
    }

    // Alternative to mViewPager.setOnClickListener, called from the adapter
    public void onViewPagerClick()
    {
        // start some activity, passing mPosition
    } 
}

页面适配器

class MyAdapter extends PagerAdapter {

    private MyObject[] mItemArray;
    private Context mContext;

    public SejoursWidgetAdapter(Context context, MyObject[] itemArray) {
        mContext = context;
        mItemArray = itemArray;
    }

    @Override
    public Object instantiateItem(View collection, int position) {

        LayoutInflater inflater = (LayoutInflater) collection.getContext()
        .getSystemService(Context.LAYOUT_INFLATER_SERVICE);

        View row = inflater.inflate(R.layout.item, null);      

        // Add click listener here because setting it directly on the ViewPager does not work (onClick not triggered)       
        row.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View v) {
                // How can I call MyFragment's onViewPagerClick() ?
            }
        }); 

        ((ViewPager) collection).addView(row);        


        return row;
    }

    /* More stuff */

}
4

2 回答 2

4

使用 ItemClick 的更改检查我的以下代码。

 class MyAdapter extends PagerAdapter {

   private MyObject[] mItemArray;
   private Context mContext;

public SejoursWidgetAdapter(Context context, MyObject[] itemArray) {
    mContext = context;
    mItemArray = itemArray;
}

@Override
public Object instantiateItem(View collection, int position) {

    LayoutInflater inflater = (LayoutInflater) collection.getContext()
    .getSystemService(Context.LAYOUT_INFLATER_SERVICE);

    View row = inflater.inflate(R.layout.item, null);      
     row .setTag(position);
    // Add click listener here because setting it directly on the ViewPager does not work (onClick not triggered)       
    row.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View v) {
            // How can I call MyFragment's onViewPagerClick() ?

          int position=(Integer) v.getTag();
     Log.v("Log_tag", "Here image is clicked"+ position);
        //now you known which Page is click you can do what you want.
        }
    }); 

    ((ViewPager) collection).addView(row);        


    return row;
}

/* More stuff */

 }
于 2012-04-20T11:16:57.610 回答
1

您还可以通过 mViewPager 获取当前页面的位置

int position = mViewPager.getCurrentItem();

代替

int position=(Integer) v.getTag();
于 2012-10-10T10:05:41.033 回答