我正在使用此代码
procedure DrawPolygonRegion(wnd : HWND; rect : TRect; NumPoints : Integer; DoStarShape : Boolean);
const
RadConvert = PI/180;
Degrees = 360;
MaxLines = 100;
var
x, y,
xCenter,
yCenter,
radius,
pts,
I : Integer;
angle,
rotation: Extended;
arPts : Array[0..MaxLines] of TPoint;
rgn : HRGN;
begin
xCenter := (rect.Right - rect.Left) div 2;
yCenter := (rect.Bottom - rect.Top) div 2;
if DoStarShape then
begin
rotation := Degrees/(2*NumPoints);
pts := 2 * NumPoints;
end
else
begin
rotation := Degrees/NumPoints; //get number of degrees to turn per point
pts := NumPoints
end;
radius := yCenter;
{This loop defines the Cartesian points of the shape. Again,
I've added 90 degrees to the rotation angle so the shapes will
stand up rather than lie on their sides. Thanks again to Terry Smithwick and
David Ullrich for their trig help on CompuServe.}
for I := 0 to pts - 1 do begin
if DoStarShape then
if (I mod 2) = 0 then //which means that
radius := Round(radius/2)
else
radius := yCenter;
angle := ((I * rotation) + 90) * RadConvert;
x := xCenter + Round(cos(angle) * radius);
y := yCenter - Round(sin(angle) * radius);
arPts[I].X := x;
arPts[I].Y := y;
end;
rgn := CreatePolygonRgn(arPts, pts, WINDING);
SetWindowRgn(wnd, rgn, TRUE);
end;
procedure TForm1.FormCreate(Sender: TObject);
begin
DrawPolygonRegion(Handle, BoundsRect, 5, True)
end;
以这种方式设置表格的形状
现在我需要在形状中绘制一个彩色边框,但我不知道如何完成这项任务。我寻找的结果是这样的。
任何想法如何完成这项任务?