如果动态意味着“在 Rails 启动时识别我的操作并动态生成路由”:
这不是我会做的事情,但它会做你想做的事,而不需要任何重定向或 method_missing 运行时开销。
在config/routes.rb
controller_filenames = Dir.new("#{Rails.root}/app/controllers").entries
controller_filenames.each do |filename|
# you could restrict to only the pages_controller.rb on the next line,
# and in that case, you could simplify even more (see next example)...
if filename =~ /_controller\.rb$/
controller_name = filename.sub(/.rb$/, "")
controller_route_name = controller_name.sub(/_controller$/, "")
controller = controller_name.camelize.constantize.new
controller.action_methods.each do |action|
# if you don't want the controller name in your path match, just omit it...
match "#{controller_route_name}/#{action}" => "#{controller_route_name}##{action}", :as => "#{controller_route_name}_#{action}"
end
end
end
如果您只想为 pages_controller.rb 文件执行此操作,则:
controller_name = "pages_controller"
controller_route_name = "pages"
controller = controller_name.camelize.constantize.new
controller.action_methods.each do |action|
# I've removed the controller_route_name from the match here...
match "#{action}" => "#{controller_route_name}##{action}", :as => "#{controller_route_name}_#{action}"
end
现在,如果动态意味着“每当我动态生成新动作时生成路由”:
你真的可以玩火。您现有的任何操作都可以定义新的操作和路由。例如,我可以定义一个路由config/routes.rb
(但这可以是任何现有的路由):
match '/dynamic_define' => 'application#dynamic_define'
将其与 in 中的方法相结合ApplicationController
(同样,这可以是任何现有操作):
def dynamic_define
method_name = params[:mname]
self.class.send(:define_method, method_name) {
render :text => "output from #{method_name}"
}
Rails.application.routes.disable_clear_and_finalize = true
Rails.application.routes.draw do
match "/#{method_name}" => "application##{method_name}", :as => "application_#{method_name}"
end
render :text => "dynamic_define just created a new action named #{method_name}"
end
在浏览器中,您可以访问:
/dynamic_define?mname=my_new_dynamic_action
# browser renders "dynamic_define just created a new action named my_new_dynamic_action"
然后访问:
/my_new_dynamic_action
# browser renders "output from my_new_dynamic_action"