1

我想找出当前系统时间和插入的数据&时间之间的差异String。我试过这个：

 try {

            String strFileDate = "2012-04-19 15:15:00";
            DateFormat formatter2 = new SimpleDateFormat("yyyy-mm-dd hh:mm:ss");
            Date date = formatter2.parse(strFileDate);
            long difference = date.getTime() - System.currentTimeMillis();
            Calendar calendar = Calendar.getInstance();
            calendar.setTimeInMillis(difference);
            Toast.makeText(getBaseContext(),
                    formatter2.format(calendar.getTime()), Toast.LENGTH_LONG)
                    .show();
        } catch (Exception e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

但它并没有给我正确的结果。我做对了吗？

更新

我尝试关注::

String strFileDate = "2012-04-19 15:15:00";
            DateFormat formatter2 = new SimpleDateFormat("yyyy-mm-dd hh:mm:ss");
            Date date = formatter2.parse(strFileDate);
            long diffInMs = date.getTime()
                    - new Date(System.currentTimeMillis()).getTime();

            long diffInSec = TimeUnit.MILLISECONDS.toSeconds(diffInMs);

            long hour = diffInSec / (1000 * 60 * 60);
            double minutes = diffInSec / (1000 * 60);
            // long diffInHour = TimeUnit.to(diffInMs);

            Toast.makeText(getBaseContext(),
                    "left time is :: " + hour + ":" + minutes,
                    Toast.LENGTH_LONG).show();

输出:: 剩余时间是:: -2 : -131.0

更新(20/4/2012)

try {
            Date dt = new Date();
            String strFileDate = "2012-04-20 13:10:00";
            DateFormat formatter2 = new SimpleDateFormat("yyyy-mm-dd hh:mm:ss");
            Date date = formatter2.parse(strFileDate);
            String s = getTimeDiff(dt, date);
            Log.i("Date is :: >>> ", s);
        } catch (Exception e) {
            e.printStackTrace();
        }
 public String getTimeDiff(Date dateOne, Date dateTwo) {
        String diff = "";
        long timeDiff = Math.abs(dateOne.getTime() - dateTwo.getTime());
        diff = String.format("%d hour(s) %d min(s)", TimeUnit.MILLISECONDS.toHours(timeDiff),
                TimeUnit.MILLISECONDS.toMinutes(timeDiff) - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(timeDiff)));
        return diff;

}

输出:: 04-20 12:48:06.629: INFO/Date is :: >>>(1295): 2183 hours(s) 38 min(s)

4

5 回答 5

5 
String strFileDate = "2012-04-19 15:15:00";
DateFormat formatter2 = new SimpleDateFormat("yyyy-mm-dd hh:mm:ss");
Date date = formatter2.parse(strFileDate);
long diffInMs = date.getTime() - new Date(System.currentTimeMillis()).getTime();


long diffInSec = TimeUnit.MILLISECONDS.toSeconds(diffInMis);

long diffInHour = TimeUnit.MILLISECONDS.toHours(diffInMis);

使用 TimeUnit 获取秒数。 http://developer.android.com/reference/java/util/concurrent/TimeUnit.html

编辑：

在此处获取TIMEUNIT 代码

public String getTimeDiff(Date dateOne, Date dateTwo) {
        String diff = "";
        long timeDiff = Math.abs(dateOne.getTime() - dateTwo.getTime());
        diff = String.format("%d hour(s) %d min(s)", TimeUnit.MILLISECONDS.toHours(timeDiff),
                TimeUnit.MILLISECONDS.toMinutes(timeDiff) - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(timeDiff)));
        return diff;
}
于 2012-04-19T10:23:08.053 回答
1

使用 JodaTime 计算周期（时差）。http://joda-time.sourceforge.net/

于 2012-04-19T10:20:25.293 回答
1 
    Calendar calendar = Calendar.getInstance();
calendar.setTime(date.getYear(),date.getMonth(),date.getDay(),date.getHourOFday(),date.getMinutes(),date.getSeconds); // not syntactically right..
long difference = System.currentTimeMillis()-calendar.getTimeInMillis();

并获得小时差异

double hour = difference/(1000*60*60);
double minutes = difference/(1000*60);
于 2012-04-19T10:26:06.977 回答
0
  • 你得到什么输出？
  • 你期望什么输出？

如果您需要以秒为单位的时间，请参阅#3960661 。

于 2012-04-19T10:20:16.857 回答
0
于 2018-02-28T22:16:27.760 回答