3

我有以下两个表：

Jobs
--------
JobNo
DivisionID

NCRs
--------
ID
JobNo
SpoilageJobNo
DivisionID

JobNo 和 DivisionID 构成 Jobs 表中的复合键（我知道，但不幸的是它必须是复合键，因为它实际上是从 4 个不同数据库中提取数据的视图），我需要将此键加入 NCR JobNo 和 SpoilageJobNo 上的表。

我尝试了以下映射：

<class name="Job" table="v_Jobs">
    <composite-id name="Key">
        <key-property name="JobNo"></key-property>
        <key-many-to-one name="Division" class="Division" column="DivisionID"/>
    </composite-id>

    <bag name="NCRs">
        <key>
            <column name="JobNo"></column>
            <column name="DivisionID"></column>
        </key>
        <one-to-many class="NCR"/>
    </bag>

    <bag name="SpoilageNCRs">
        <key>
            <column name="SpoilageJobNo"></column>
            <column name="DivisionID"></column>
        </key>
        <one-to-many class="NCR"/>
    </bag>
</class>

<class name="NCR" table="NCRs">
    <id name="ID">
        <generator class="identity"></generator>
    </id>

    <many-to-one name="Division"
                 class="Division"
                 column="DivisionID">
    </many-to-one>

    <many-to-one name="Job"
                 class="Job"
                 column="JobNo">
    </many-to-one>

    <many-to-one name="SpoilageJob"
                 class="Job"
                 column="SpoilageJobNo">
    </many-to-one>
</class>

但我只是得到错误Foreign key (FK480F1031931B2CA4:NCRs [JobNo])) must have same number of columns as the referenced primary key (v_Jobs [JobNo, DivisionID])

4

1 回答 1

0

这是汤姆对他的问题的回答：

啊哈，我想我明白了。我已经用这个更新了我的 NCR 映射：

<many-to-one name="Job" class="Job">
    <column name="JobNo"></column>
    <column name="DivisionID"></column>
</many-to-one>

<many-to-one name="SpoilageJob" class="Job">
    <column name="SpoilageJobNo"></column>
    <column name="DivisionID"></column>
</many-to-one>
于 2016-02-22T19:48:54.983 回答