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我有一组具有特定结构的文件：

COMPANY_DE-Actual-Contents-of-File-RGB-ENG.pdf

分解：

  • COMPANY -> 公司名称，固定
  • DE -> 办公室位置，固定选项：'_DE'、'_BE' 或不存在于不依赖于位置的文件，如果存在总是以下划线和公司名称开头
  • Actual-Contents-of-File，用破折号粘合的字符串
  • RGB -> 颜色模式，固定选项：'RGB'、'CMYK'、'PMS'，或不用于非颜色相关文件
  • ENG -> 文件语言，固定选项：'GER'、'ENG'，或不存在非文本相关文件
  • pdf -> 扩展名，可以是任何东西

在最好的情况下，我的结果将是一个包含上述信息和命名键但不知道从哪里开始的数组。

帮助将不胜感激！

谢谢， 纳尔

抱歉，不清楚，但文件名中并不总是存在一些变量：-DE -> 固定选项：'_DE'，'_BE'，或不存在 -RGB -> Colormode，固定选项：'RGB'，' CMYK'、'PMS' 或不存在 - ENG -> 文件语言，固定选项：'GER'、'ENG' 或不存在

4

5 回答 5

1

尝试

$string = "COMPANY_DE-Actual-Contents-of-File-RGB-ENG.pdf";
$array = preg_split('/[-_\.]/', $string);

$len = count($array);
$struct = array($array[0], $array[1], '', $array[$len-3], $array[$len-2], $array[$len-1]);
unset($array[0], $array[1], $array[$len-3], $array[$len-2], $array[$len-1]);
$struct[2] = implode('-', $array);
var_dump($struct);

-

array
  0 => string 'COMPANY' (length=7)
  1 => string 'DE' (length=2)
  2 => string 'Actual-Contents-of-File' (length=23)
  3 => string 'RGB' (length=3)
  4 => string 'ENG' (length=3)
  5 => string 'pdf' (length=3)
于 2012-04-19T08:17:47.240 回答
1

如果可能，尽量不要使用正则表达式，或者让它们尽可能简单。

$text = "COMPANY_DE-Actual-Contents-of-File-RGB-ENG.pdf";
$options_location = array('DE','BE');
$options_color = array('RGB','CMYK','PMS');
$options_language = array('ENG','GER');

//Does it have multiple such lines? In that case this:
$lines = explode("\n",$text);
//Then loop over this with a foreach, doing the following for each line:

$parts = preg_split('/[-_\.]/', $line);
$data = array(); //result array
$data['company'] = array_shift($parts); //The first element is always the company
$data['filetype'] = array_pop($parts); //The last bit is always the file type
foreach($parts as $part) { //we'll have to test each of the remaining ones for what it is
    if(in_array($part,$options_location))
        $data['location'] = $part;
    elseif(in_array($part,$options_color))
        $data['color'] = $part;
    elseif(in_array($part,$options_language))
        $data['lang'] = $part;
    else
        $data['content'] = isset($data['content']) ? $data['content'].' '.$part : $part; //Wasn't any of the others so attach it to the content
}

这也更容易理解，而不必弄清楚正则表达式到底在做什么。

请注意，这假定内容的任何部分都不能是为位置、颜色或语言保留的单词之一。如果这些可能出现在内容中，您将必须添加条件，例如isset($data['location'])检查是否已经找到另一个位置，如果是，则将正确的位置添加到内容中，而不是将其存储为位置。

于 2012-04-19T08:41:54.533 回答
0

像这样的东西：

preg_match('#^([^_]+)(_[^-]+)?-([\w-]+)-(\w+)-(\w+)(\.\w+)$#i', 'COMPANY_DE-Actual-Contents-of-File-RGB-ENG.pdf', $m);

preg_match('#^([^_]+)(_[^-]+)?-([\w-]+)-(\w+)[_-]([^_]+)(\.\w+)$#i', 'COMPANY_DE-Actual-Contents-of-File-RGB-ENG.pdf', $m); // for both '_' and '-'

preg_match('#^(\p{Lu}+)(-\p{Lu}+)?-([\w]+)(\-(\p{Lu}+))?(\-(\p{Lu}+))?(\.\w+)$#', 'COMPANY-NL-Actual_Contents_of_File-RGB-ENG.pdf', $m); // if filename parts divider is strictly '-'

var_dump($m);

在最后一个变体中，当您询问是否没有国家代码 (-NL) 时，它将为 NULL。但是对于颜色和语言代码，它不是。自己尝试一下，你就会知道它是如何工作的！

于 2012-04-19T08:14:02.527 回答
0

受@Armatus 的启发，我构建了以下似乎是故障安全的：

$string = "COMPANY_DE-Actual-Contents+of-File-RGB-ENG.pdf";
$options_location = array('DE','BE');
$options_color = array('RGB','CMYK','PMS');
$options_language = array('ENG','GER');
$parts = preg_split( '/[\.\-\_]/', $string, NULL, PREG_SPLIT_NO_EMPTY );

$data = array();
$data['company'] = array_shift($parts);
$data['filetype'] = array_pop($parts);

if( in_array( $parts[0], $options_location ) ){
$data['location'] = array_shift($parts);
}else{
$data['location'] = NULL;
};

if( in_array( end( $parts), $options_language ) ){
$data['language'] = array_pop($parts);
}else{
$data['language'] = NULL;
};

if( in_array( end( $parts), $options_color ) ){
$data['colormode'] = array_pop($parts);
}else{
$data['colormode'] = NULL;
};

$data['content'] = implode( ' ', $parts );
print_r( $data );
于 2012-04-20T06:39:52.287 回答
0

怎么样：

$files = array(
    'COMPANY_DE-Actual-Contents-of-File-RGB-ENG.pdf',
    'COMPANY_BE-Actual-Contents-of-File-CMYK-ENG.pdf',
    'COMPANY_DE-Actual-Contents-of-File-PMS-GER.doc',
    'COMPANY-Actual-Contents-of-File-PMS-GER.doc',
    'COMPANY-Actual-Contents-of-File-GER.doc',
    'COMPANY-Actual-Contents-of-File.doc',
);

foreach($files as $file) {
    preg_match('/^(?<COMPANY>.*?)_?(?<LOCATION>DE|BE)?-(?<CONTENT>.*?)-?(?<COLOR>RGB|CMYK|PMS)?-?(?<LANG>ENG|GER)?\.(?<EXT>[^.]+)$/', $file, $m);
    echo "\nfile=$file\n";
    echo "COMPANY: ",$m['COMPANY'],"\n";
    echo "LOCATION: ",$m['LOCATION'],"\n";
    echo "CONTENT: ",$m['CONTENT'],"\n";
    echo "COLOR: ",$m['COLOR'],"\n";
    echo "LANG: ",$m['LANG'],"\n";
    echo "EXT: ",$m['EXT'],"\n";
}

输出：

file=COMPANY_DE-Actual-Contents-of-File-RGB-ENG.pdf
COMPANY: COMPANY
LOCATION: DE
CONTENT: Actual-Contents-of-File
COLOR: RGB
LANG: ENG
EXT: pdf

file=COMPANY_BE-Actual-Contents-of-File-CMYK-ENG.pdf
COMPANY: COMPANY
LOCATION: BE
CONTENT: Actual-Contents-of-File
COLOR: CMYK
LANG: ENG
EXT: pdf

file=COMPANY_DE-Actual-Contents-of-File-PMS-GER.doc
COMPANY: COMPANY
LOCATION: DE
CONTENT: Actual-Contents-of-File
COLOR: PMS
LANG: GER
EXT: doc

file=COMPANY-Actual-Contents-of-File-PMS-GER.doc
COMPANY: COMPANY
LOCATION:
CONTENT: Actual-Contents-of-File
COLOR: PMS
LANG: GER
EXT: doc

file=COMPANY-Actual-Contents-of-File-GER.doc
COMPANY: COMPANY
LOCATION:
CONTENT: Actual-Contents-of-File
COLOR:
LANG: GER
EXT: doc

file=COMPANY-Actual-Contents-of-File.doc
COMPANY: COMPANY
LOCATION:
CONTENT: Actual-Contents-of-File
COLOR:
LANG:
EXT: doc
于 2012-04-19T12:04:02.180 回答