php - 通过比较另一个数组的键从一个数组中删除数组值

Question

假设我有第一个数组 $aAllCities 作为

Array
(
   [21] => London
   [9]  => Paris
   [17] => New York
   [3]  => Tokyo
   [25] => Shanghai
   [11] => Dubai
   [37] => Mumbai
)

另一个数组 $aNotSupportedCities 为

Array
(
   [0] => 37
   [1] => 25
   [2] => 11
)

有可能得到这样的数组吗？

Array
(
   [21] => London
   [9]  => Paris
   [17] => New York
   [3]  => Tokyo
)

我想删除其他数组中存在的那些键的数组值

score 2 · Accepted Answer

foreach($aAllCities as $key => $value) {
    if(in_array($key,$aNotSupportedCities)) {
        unset($aAllCities[$key]); 
    }

}

score 1 · Accepted Answer

试试这个：

$aAllCities = array_flip( $aAllCities );
$aAllCities = array_diff( $aAllCities, $aNotSupportedCities );
$aAllCities = array_flip( $aAllCities );

希望这可以帮助。

score 1 · Accepted Answer

其他答案是正确的，但更顺畅、更快的方法是：
$supportedCities = array_diff_key($aAllCities, $aNotSupportedCities);

这将返回所有$aAllCities没有键的值$aNotSupportedCities

请注意，这将通过它们的键比较两个数组，因此您需要使您的$aNotSupportedCities外观如下所示：

Array
(
   [37] => something
   [25] => doesn't really matter
   [11] => It's not reading this
)

祝你好运。

score 0 · Accepted Answer

$new = $aAllCities;
foreach($aNotSupportedCities as $id) {
  if (isset($new[$id]) {
    unset($new[$id]);
  }
}

score 0 · Accepted Answer

0

$supportedCities = array_diff_key($aAllCities, array_values($aNotSupportedCities));

于 2012-04-19T07:40:14.920 回答

5 回答 5