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在下面的程序中，我试图将三角形逆时针旋转 45 度。多边形确实旋转到某个角度并平移到其他地方。请让我知道如何解决此问题。

#include<stdio.h>
#include<conio.h>
#include<graphics.h>
#include<math.h>

int main(void)
{
 int poly[8], rpoly[8],angle;
 int gd = DETECT, gm;
 initgraph(&gd,&gm,"C:\\TC\\BGI");

 printf("\n Enter co-ordinates for Triangle :  \n\n");

 printf("Vertex 1 (x,y)  : ");
 scanf("%d %d", &poly[0], &poly[1]);
 printf("Vertex 2 (x,y)  : ");
 scanf("%d %d", &poly[2], &poly[3]);
 printf("Vertex 3 (x,y)  : ");
 scanf("%d %d", &poly[4], &poly[5]);
 poly[6] = poly[0];
 poly[7] = poly[1];

 setcolor(2);
 drawpoly(4,poly);

 angle = 45;
 rpoly[0] = poly[0]*cos(angle) - poly[1]*sin(angle);
 rpoly[1] = poly[0]*sin(angle) + poly[1]*cos(angle);

 rpoly[2] = poly[2]*cos(angle) - poly[3]*sin(angle);
 rpoly[3] = poly[2]*sin(angle) + poly[3]*cos(angle);

 rpoly[4] = poly[4]*cos(angle) - poly[5]*sin(angle);
 rpoly[5] = poly[4]*sin(angle) + poly[5]*cos(angle);

 rpoly[6] = rpoly[0];
 rpoly[7] = rpoly[1];

 setcolor(4);
 drawpoly(4,rpoly);

 getch();
 closegraph();
 return 0;
}

输出： 在此处输入图像描述

编辑1：

在输出中，红色三角形（即旋转后的三角形）看起来比原来的大。

新代码

#include<stdio.h>
#include<conio.h>
#include<graphics.h>
#include<math.h>

int main(void)
{
 int poly[8], rpoly[8], angle, centroid_x, centroid_y,i;
 int gd = DETECT, gm;
 initgraph(&gd,&gm,"C:\\TC\\BGI");

 printf("\n Enter co-ordinates for Triangle :  \n\n");

 printf("Vertex 1 (x,y)  : ");
 scanf("%d %d", &poly[0], &poly[1]);
 printf("Vertex 2 (x,y)  : ");
 scanf("%d %d", &poly[2], &poly[3]);
 printf("Vertex 3 (x,y)  : ");
 scanf("%d %d", &poly[4], &poly[5]);
 poly[6] = poly[0];
 poly[7] = poly[1];

 setcolor(2);
 drawpoly(4,poly);

 angle = 45 * 2 * 3.14 / 360;
 centroid_x =  (poly[0] + poly[2] + poly[4]) / 3;
 centroid_y =  (poly[1] + poly[3] + poly[5]) / 3;

 rpoly[0] = (poly[0] - centroid_x) * cos(angle)  -  (poly[1] - centroid_y) * sin(angle)  +  centroid_x;
 rpoly[1] = (poly[0] - centroid_x) * sin(angle)  -  (poly[1] - centroid_y) * cos(angle)  +  centroid_y;

 rpoly[2] = (poly[2] - centroid_x) * cos(angle)  -  (poly[3] - centroid_y) * sin(angle)  +  centroid_x;
 rpoly[3] = (poly[2] - centroid_x) * sin(angle)  -  (poly[3] - centroid_y) * cos(angle)  +  centroid_y;

 rpoly[4] = (poly[4] - centroid_x) * cos(angle)  -  (poly[5] - centroid_y) * sin(angle)  +  centroid_x;
 rpoly[5] = (poly[4] - centroid_x) * sin(angle)  -  (poly[5] - centroid_y) * cos(angle)  +  centroid_y;

 rpoly[6] = rpoly[0];
 rpoly[7] = rpoly[1];

 setcolor(4);
 drawpoly(4,rpoly);

 for(i=0;i<7;i++)
 {printf("\n %d", &rpoly[i]);}

 getch();
 closegraph();
 return 0;
}

输出： 在此处输入图像描述

编辑2：

更正 Y 项后的代码：

#include<stdio.h>
#include<conio.h>
#include<graphics.h>
#include<math.h>

int main(void)
{
 int poly[8], rpoly[8], angle, centroid_x, centroid_y,i;
 int gd = DETECT, gm;
 initgraph(&gd,&gm,"C:\\TC\\BGI");

 printf("\n Enter co-ordinates for Triangle :  \n\n");

 printf("Vertex 1 (x,y)  : ");
 scanf("%d %d", &poly[0], &poly[1]);
 printf("Vertex 2 (x,y)  : ");
 scanf("%d %d", &poly[2], &poly[3]);
 printf("Vertex 3 (x,y)  : ");
 scanf("%d %d", &poly[4], &poly[5]);
 poly[6] = poly[0];
 poly[7] = poly[1];

 setcolor(2);
 drawpoly(4,poly);

 angle = 45 * 2 * 3.14 / 360;
 centroid_x =  (poly[0] + poly[2] + poly[4]) / 3;
 centroid_y =  (poly[1] + poly[3] + poly[5]) / 3;

 rpoly[0] = (poly[0] - centroid_x) * cos(angle)  -  (poly[1] - centroid_y) * sin(angle)  +  centroid_x;
 rpoly[1] = (poly[0] - centroid_x) * sin(angle)  +  (poly[1] - centroid_y) * cos(angle)  +  centroid_y;

 rpoly[2] = (poly[2] - centroid_x) * cos(angle)  -  (poly[3] - centroid_y) * sin(angle)  +  centroid_x;
 rpoly[3] = (poly[2] - centroid_x) * sin(angle)  +  (poly[3] - centroid_y) * cos(angle)  +  centroid_y;

 rpoly[4] = (poly[4] - centroid_x) * cos(angle)  -  (poly[5] - centroid_y) * sin(angle)  +  centroid_x;
 rpoly[5] = (poly[4] - centroid_x) * sin(angle)  +  (poly[5] - centroid_y) * cos(angle)  +  centroid_y;

 rpoly[6] = rpoly[0];
 rpoly[7] = rpoly[1];

 setcolor(4);
 drawpoly(4,rpoly);

// for(i=0;i<8;i++)
// {printf("\n %d", &rpoly[i]);}

 getch();
 closegraph();
 return 0;
}

输出：

在此处输入图像描述

4

2 回答 2

5

两个问题：sin并cos以弧度而不是度数为参数；你可能想围绕它的中心旋转你的多边形，而不是大约 (0, 0)。

要解决第一个问题，请更改：

angle = 45;

至：

angle = 45.0 * 2.0 * M_PI / 360.0;

要解决第二个问题，您需要首先计算多边形的质心，然后平移顶点相对于质心的坐标。

于 2012-04-18T16:07:00.110 回答
4 
 rpoly[0] = (poly[0] - centroid_x) * cos(angle)  -  (poly[1] - centroid_y) * sin(angle)  +  centroid_x;
 rpoly[1] = (poly[0] - centroid_x) * sin(angle)  +  (poly[1] - centroid_y) * cos(angle)  +  centroid_y;

rpoly[1] 是在 rpoly[0] 更改后计算的。

尝试这个;

float newX = .......;
rpoly[0] = newX;
float newY = .......;
rpoly[1] = newY;
于 2012-11-03T10:48:16.937 回答