如何在 android 1.6 或 2 中创建这样的列表视图(因为 renderscript,它仅适用于 3 或更高版本,但我需要 list 才能在几乎所有 android 上工作):
问问题
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1 回答
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我Camera.setTranslate(x, 0, z)
在 drawChild 中使用过,其中更改了旋转虚拟化的 x 位置和重叠的 z 位置。然后有重叠的问题,因为最后一个项目在顶部,第一个在底层。因此,在onCreate()
调用this.setChildrenDrawingOrderEnabled(true)
和覆盖的方法protected int getChildDrawingOrder (int childCount, int i) {}
中,我可以更改中间行和后面行的顺序。这个想法是由 Renard 提出的,他在我的其他帖子中向我提出了关于这里几乎相同的事情的建议。
我的 getChildDrawingOrder(int, int) 实现需要重叠:
@Override
protected int getChildDrawingOrder (int childCount, int i) {
int centerChild = 0;
//find center row
if ((childCount % 2) == 0) { //even childCount number
centerChild = childCount / 2; // if childCount 8 (actualy 0 - 7), then 4 and 4-1 = 3 is in centre.
int otherCenterChild = centerChild - 1;
//Which more in center?
View child = this.getChildAt(centerChild);
final int top = child.getTop();
final int bottom = child.getBottom();
//if this row goes through center then this
final int absParentCenterY = getTop() + getHeight() / 2;
//Log.i("even", i + " from " + (childCount - 1) + ", while centerChild = " + centerChild);
if ((top < absParentCenterY) && (bottom > absParentCenterY)) {
//this child is in center line, so it is last
//centerChild is in center, no need to change
} else {
centerChild = otherCenterChild;
}
}
else {//not even - done
centerChild = childCount / 2;
//Log.i("not even", i + " from " + (childCount - 1) + ", while centerChild = " + centerChild);
}
int rez = i;
//find drawIndex by centerChild
if (i > centerChild) {
//below center
rez = (childCount - 1) - i + centerChild;
} else if (i == centerChild) {
//center row
//draw it last
rez = childCount - 1;
} else {
//above center - draw as always
// i < centerChild
rez = i;
}
//Log.i("return", "" + rez);
return rez;
}
我希望这篇文章对将来的人有所帮助
屏幕截图实际上与我在问题中提到的几乎相同。我使用了 alpha,所以叠加的项目有点透明:
于 2012-04-23T10:15:33.897 回答