0

我有一张这样的桌子：

ORDER_ID   CODE1   CODE2   CODE3   STATUS
1          '001'   'BIGP'  NULL    4
2          '002'   'BIGP'  NULL    1
3          '001'    NULL   NULL    6
4          '002'    NULL   'L'     1

第二张桌子像这样：

ADDRESS_ID   ORDER_ID  TYPE   ADD_DATE       CATEGORY
1            1         'K1'   '2010-01-01'   'CLIENT'
2            1         'D1'   '2010-01-02'   'SYSTEM'
3            2         'D2'   '2010-01-02'   'SYSTEM'
4            2         'D2'   '2010-02-01'   'CLIENT'

如果对于每个具有以下内容的订单，我必须做什么：

  • 状态不在 (4,6)
  • 代码1='002'
  • (code2=null and code3=null) or (code2 in ('BIGA', 'BIGP') and code3=null) or (code2=NULL and code3 = 'L')

我必须选择一个类型为“D2”或“K1”的地址（D2 具有更高的优先级，因此如果有 2 个地址，一个 K1 和第二个 D2，我必须选择 D2）。
如果没有任何类型为 D2 或 K1 的地址，我必须为该订单选择类别为“客户”的最旧地址。

这是我创建的：

SELECT TOP 1000 o.order_Id
              , a.Address_Id
              , a.Zip
            --, *
FROM orders o
 address a
    ON a.order_Id = o.order_Id
WHERE
 (a.Type='D2' OR a.Type='K1')
 AND o.Status NOT IN (4, 6)
 AND code1='002'
 AND ((code2 IS NULL AND code3 IS NULL) OR (code2 IN ('BIGA', 'BIGP') AND code3 IS NULL) OR (code2 IS NULL AND code3 = 'L'))
4

2 回答 2

3

您可以为该任务使用CROSS APPLYderived table ，因为它允许在.

SELECT TOP 1000 o.order_Id
              , a.Address_Id
              , a.Zip
            --, *
FROM orders o
CROSS APPLY
(
 select TOP 1
        a.Address_Id,
        a.Zip
   from address a
  WHERE a.order_Id = o.order_Id
  ORDER BY case a.Type 
                when 'D2' then 1 
                when 'K1' then 2 
                else 3 
            end,
        a.ADD_DATE
) a
WHERE
 o.Status NOT IN (4, 6)
 AND code1='002'
 AND ((code2 IS NULL AND code3 IS NULL) OR (code2 IN ('BIGA', 'BIGP') AND code3 IS NULL) OR (code2 IS NULL AND code3 = 'L'))

除此之外，您可能会以每个订单的最小类型加入派生地址表：

from orders o
inner join address a
  ON a.order_Id = o.order_Id
inner join
(
  select a.order_id, a.Type,
         row_number () over (partition by a.order_id
                             order by case a.Type when 'D2' then 1 
                                                  when 'K1' then 2 
                                                  else 3 
                                       end, 
                                      a.ADD_DATE) rn
    from Address a
   group by a.order_id, a.Type
) onlyOneAddress
  on a.order_id = onlyOneAddress.order_id
 and a.type = onlyOneAddress.type
 and onlyOneAddress.rn = 1
于 2012-04-18T12:35:23.110 回答
0

只需按 [Type] desc 添加顺序，它将显示高优先级

于 2012-04-18T12:00:10.187 回答