2

我有以下 GraphML 文件“mygraph.gml”，我想用一个简单的 python 脚本对其进行解析：

这表示一个简单的图，其中包含 2 个节点“node0”、“node1”和它们之间的一条边

<?xml version="1.0" encoding="UTF-8"?>
<graphml xmlns="http://graphml.graphdrawing.org/xmlns"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://graphml.graphdrawing.org/xmlns
         http://graphml.graphdrawing.org/xmlns/1.0/graphml.xsd">
  <key id="name" for="node" attr.name="name" attr.type="string"/>
  <key id="weight" for="edge" attr.name="weight" attr.type="double"/>
  <graph id="G" edgedefault="directed">
    <node id="n0">
      <data key="name">node1</data>
    </node>
    <node id="n1">
      <data key="name">node2</data>
    </node>
<edge source="n1" target="n0">
  <data key="weight">1</data>
</edge>
  </graph>
</graphml>

这表示一个具有两个节点 n0 和 n1 的图，它们之间有一条权重为 1 的边。我想用python解析这个结构。

我在 lxml 的帮助下写了一个脚本（我需要使用它，因为数据集比这个简单的例子大得多，超过 10^5 个节点，python minidom 太慢了）

import lxml.etree as et

tree = et.parse('mygraph.gml')

root = tree.getroot()

graphml = {
"graph": "{http://graphml.graphdrawing.org/xmlns}graph",
"node": "{http://graphml.graphdrawing.org/xmlns}node",
"edge": "{http://graphml.graphdrawing.org/xmlns}edge",
"data": "{http://graphml.graphdrawing.org/xmlns}data",
"label": "{http://graphml.graphdrawing.org/xmlns}data[@key='label']",
"x": "{http://graphml.graphdrawing.org/xmlns}data[@key='x']",
"y": "{http://graphml.graphdrawing.org/xmlns}data[@key='y']",
"size": "{http://graphml.graphdrawing.org/xmlns}data[@key='size']",
"r": "{http://graphml.graphdrawing.org/xmlns}data[@key='r']",
"g": "{http://graphml.graphdrawing.org/xmlns}data[@key='g']",
"b": "{http://graphml.graphdrawing.org/xmlns}data[@key='b']",
"weight": "{http://graphml.graphdrawing.org/xmlns}data[@key='weight']",
"edgeid": "{http://graphml.graphdrawing.org/xmlns}data[@key='edgeid']"
}

graph = tree.find(graphml.get("graph"))
nodes = graph.findall(graphml.get("node"))
edges = graph.findall(graphml.get("edge"))

该脚本正确获取节点和边，以便我可以简单地迭代它们

for n in nodes:
    print n.attrib

或类似的边缘：

for e in edges:
    print (e.attrib['source'], e.attrib['target'])

但我真的不明白如何获取边缘或节点的“数据”标签以打印边缘权重和节点标签“名称”。

这对我不起作用：

weights = graph.findall(graphml.get("weight"))

最后一个列表总是空的。为什么？我错过了一些东西，但不明白是什么。

4

1 回答 1

3

您不能一次完成，但是对于找到的每个节点，您可以使用数据的键/值构建一个字典：

graph = tree.find(graphml.get("graph"))
nodes = graph.findall(graphml.get("node"))
edges = graph.findall(graphml.get("edge"))

for node in nodes + edges:
    attribs = {}
    for data in node.findall(graphml.get('data')):
        attribs[data.get('key')] = data.text
    print 'Node', node, 'have', attribs

它给出了结果：

Node <Element {http://graphml.graphdrawing.org/xmlns}node at 0x7ff053d3e5a0> have {'name': 'node1'}
Node <Element {http://graphml.graphdrawing.org/xmlns}node at 0x7ff053d3e5f0> have {'name': 'node2'}
Node <Element {http://graphml.graphdrawing.org/xmlns}edge at 0x7ff053d3e640> have {'weight': '1'}
于 2012-04-18T09:49:01.590 回答