我有一些作业要完成，直到我到达最后一步，我现在很难过，我真的很感激一些帮助。
该项目的前提是创建一个给定电话号码的可能单词文件。用户应输入格式为“###-####”的数字。然后代码将连字符拉出并将电话号码发送到方法wordGenerator。我知道到目前为止一切正常。当输出单词的不同可能性时，我遇到了问题。这是我的方法的样子：
// function to form words based on phone number
void wordGenerator( const int * const n )
{
// set output stream and open output file
/* Write a declaration for an ofstream object called
outFile to open the file "phone.dat" */
ofstream outFile("phone.dat");
// letters corresponding to each number
/* Write a declaration for an array of 10 const char *'s
called phoneLetters. Use an initializer list to assign
each element of the array the corresponding string of
three letters. Use dummy characters for 0 and 1 */
const char * phoneLetters[] = {"###", "###", "ABC", "DEF", "GHI",
"JKL", "MNO", "PRS", "TUV", "WXY"};
// terminate if file could not be opened
/* Write code to check if the file was opened successfully,
and terminate if not */
if( !outFile )
{
cerr << "The file could not be opened";
exit(1);
}
int count = 0; // number of words found
// output all possible combinations
for ( int i1 = 0; i1 <= 2; i1++ )
{
for ( int i2 = 0; i2 <= 2; i2++ )
{
for ( int i3 = 0; i3 <= 2; i3++ )
{
for ( int i4 = 0; i4 <= 2; i4++ )
{
for ( int i5 = 0; i5 <= 2; i5++ )
{
for ( int i6 = 0; i6 <= 2; i6++ )
{
for ( int i7 = 0; i7 <= 2; i7++ )
{
/* Write a series of cascaded stream insertion
operations to output a set of seven letters
to outFile, followed by a space */
outFile << phoneLetters[i7 + 2] << phoneLetters[i6 + 2] << phoneLetters[i5 + 2] << phoneLetters[i4 + 2] << phoneLetters[i3 + 2] << phoneLetters[i2 + 2]
<< phoneLetters[i1 + 2] << ' ';
if ( ++count % 9 == 0 ) // form rows
outFile << '\n';
} // end for
} // end for
} // end for
} // end for
} // end for
} // end for
} // end for
// output phone number
outFile << "\nPhone number is ";
for ( int i = 0; i < 7; i++ )
{
if ( i == 3 )
outFile << '-';
outFile << n[ i ];
} // end for
/* Write a statement to close the ouput file */
outFile.close();
system("pause");
} // end function wordGenerator
不幸的是，我得到了一个代码框架，并被告知要填写空白以完成作业。评论被阻止的任何地方（/ * * /）都是我必须填写代码的地方。
我不确定我需要做什么来输出可能单词的正确格式。我尝试搜索谷歌，但我发现的所有结果都使用了一个更简单（在我看来）的 switch 语句来实现这一点，并且我受限于模板:(
感谢所有帮助，即使是朝着正确的方向轻推。
编辑：我只是想到了另一件事。我觉得如果有人甚至可以帮助我弄清楚如何单独遍历 phoneLetters[] 的字符而不是一个块，那将是向前迈出的重要一步。示例：当读取电话号码的数字“2”而不是打印“ABC”时，为所有可能的组合打印“A”，然后转到“B”。
编辑：这是我的主要（）：
int main()
{
int phoneNumber[ 7 ] = { 0 }; // holds phone number
// prompt user to enter phone number
cout << "Enter a phone number (digits 2 through 9) "
<< "in the form: xxx-xxxx\n";
// loop 8 times: 7 digits plus hyphen;
// hyphen is not placed in phoneNumber
for ( int u = 0, v = 0; u < 8; u++ )
{
int i = cin.get();
// test if i is between 0 and 9
if ( i >= '0' && i <= '9' )
phoneNumber[ v++ ] = i - '0';
} // end for
wordGenerator( phoneNumber ); // form words from phone number
return 0;
} // end main