1

目前我有2个不同的mysql查询：

查询 1

SELECT monthname( calendar.datefield ) AS date,
    year(calendar.datefield) as year, calendar.datefield, COUNT(all_griefs_tbl.actioned_status ) AS total_griefs,
    all_griefs_tbl.actioned_status, all_griefs_tbl.game
FROM all_griefs_tbl 
RIGHT JOIN calendar 
  ON ( DATE(all_griefs_tbl.actioned_date ) = calendar.datefield )
    AND all_griefs_tbl.actioned_status = 'accepted'
WHERE calendar.datefield
  BETWEEN DATE_ADD(CURDATE(), INTERVAL -12 MONTH)  AND CURDATE()
GROUP BY year( calendar.datefield ) DESC , month( calendar.datefield ) DESC

查询 2

SELECT monthname( calendar.datefield ) AS date, 
    year(calendar.datefield ) AS year, calendar.datefield,
    COUNT(all_griefs_tbl.actioned_status ) AS total_submitted,
    all_griefs_tbl.actioned_status, all_griefs_tbl.game 
FROM all_griefs_tbl 
RIGHT JOIN calendar 
  ON ( DATE( all_griefs_tbl.date ) = calendar.datefield ) 
WHERE calendar.datefield BETWEEN DATE_ADD( CURDATE( ) , INTERVAL -12 MONTH ) AND CURDATE( ) 
GROUP BY year( calendar.datefield ) DESC , month( calendar.datefield ) DESC

现在这些之间的区别在于查询 1 我正在计算每月接受的悲伤的数量，而在查询 2 中我正在计算每月提交的记录数 - 计算不同的列

我想做的是a）将其放入单个查询中或b）能够将结果合并到1个表中。

我希望输出如下：

    Month         Year          Total Griefs  Total Submitted
    ------------  ------------  ------------  ------------  
    April         2012          14            2      
    March         2012          0             8
    February      2012          0             6
    January       2012          0             13
    December      2011          0             7
    November      2011          0             10
    October       2011          0             0
    September     2011          0             0
    August        2011          0             6
    July          2011          0             3
    June          2011          0             2
    May           2011          0             0
    April         2011          0             0

这是可能的，还是我完全找错了树？

谢谢！

4

3 回答 3

3

您可以在一个查询中执行此操作：

SELECT 
    monthname( calendar.datefield ) AS date,
    year(calendar.datefield) as year, 
    calendar.datefield,
    SUM(IF(all_griefs_tbl.actioned_status = 'accepted', 1, 0)) AS total_griefs,
    COUNT(all_griefs_tbl.actioned_status ) AS total_submitted,
    all_griefs_tbl.actioned_status, 
    all_griefs_tbl.game 
FROM 
    all_griefs_tbl 
RIGHT JOIN 
    calendar ON ( DATE(all_griefs_tbl.actioned_date ) = calendar.datefield ) 
WHERE 
    calendar.datefield BETWEEN DATE_ADD(CURDATE(), INTERVAL -12 MONTH)  AND CURDATE() 
GROUP BY year( calendar.datefield ) DESC , 
    month( calendar.datefield ) DESC

编辑：这有点不正统，但它（很可能）会给你你所追求的：

SELECT
    month(date_add(curdate(), interval seq.mm months)),
    year(date_add(curdate(), interval seq.mm months)),
    (SELECT count(1)
       FROM all_griefs_tbl
      WHERE actioned_status = 'accepted'
        AND month(action_date) = month(date_add(curdate(), interval seq.mm months))
        AND year(action_date) = year(date_add(curdate(), interval seq.mm months))) as total_griefs
    (SELECT count(1)
       FROM all_griefs_tbl
        AND month(date) = month(date_add(curdate(), interval seq.mm months))
        AND year(date) = year(date_add(curdate(), interval seq.mm months))) as submitted_griefs
FROM
    (SELECT -12 as mm UNION SELECT -11  as mmUNION SELECT -10  as mmUNION SELECT -9  as mm
     UNION SELECT -8 as mm UNION SELECT -7  as mm UNION SELECT -6 as mm UNION SELECT -5 as mm
     UNION SELECT -4 as mm UNION SELECT -3 as mm UNION SELECT -2 as mm UNION SELECT -1 as mm) seq
ORDER BY
    mm
于 2012-04-17T15:20:47.820 回答
0

如果输出与 2 个查询相同，则可以UNION与查询一起使用。

所以添加NULL AS total_griefs,和NULL AS total_submitted,查询，所以输出匹配

于 2012-04-17T15:19:45.077 回答
0

试试这个（我真的无法测试它）

SELECT monthname(calendar.datefield) AS date, 
       year(calendar.datefield) as year, 
       calendar.datefield, 
       SUM(CASE all_griefs_tbl.actioned_status 
               WHEN 'accepted' THEN 1 
               ELSE 0 
           END CASE) AS total_griefs,
       COUNT(all_griefs_tbl.actioned_status) AS total_submitted,
       all_griefs_tbl.actioned_status, 
       all_griefs_tbl.game 
FROM all_griefs_tbl RIGHT JOIN calendar 
    ON DATE(all_griefs_tbl.actioned_date) = calendar.datefield 
WHERE calendar.datefield 
    BETWEEN DATE_ADD(CURDATE(), INTERVAL -12 MONTH) AND CURDATE() 
GROUP BY year(calendar.datefield) DESC, 
         month(calendar.datefield) DESC
于 2012-04-17T15:22:14.430 回答