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我正在执行一系列批处理文件，我只需要我的 java 程序等待第一个批处理文件退出然后执行下一个。发生的事情是每件事都在没有退出之前执行的文件的情况下执行。

这是我的代码，我正在循环运行它

String cmd = "cmd /c start /min file1.bat"; 

Process pr = Runtime.getRuntime().exec(cmd);

pr.waitFor();
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4 回答 4

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Though I'm using Linux, this should apply to Windows as well. The below sample code executes a shell process multiple times, waiting for each process to complete before continuing:

import java.util.Date;
public class Test {
    public static void main(final String[] args) {
        for (int i = 0; i < 5; i++) {
            System.out.println("Executing command " + i + ": " + (new Date()));
            try {
                final Process p = new ProcessBuilder("sh", "-c", "sleep 2;").redirectErrorStream(true).start();
                p.waitFor();
            } catch (final Throwable t) {
                t.printStackTrace();
            }
        }
    }
}

This outputs:

Executing command 0: Tue Apr 17 09:19:55 EDT 2012
Executing command 1: Tue Apr 17 09:19:57 EDT 2012
Executing command 2: Tue Apr 17 09:20:00 EDT 2012
Executing command 3: Tue Apr 17 09:20:02 EDT 2012
Executing command 4: Tue Apr 17 09:20:04 EDT 2012

Printing the result (exit value) of Runtime.exec(String) using a value of sh -c 'sleep 2;', I get 2 (failed execution); but the result of Runtime.exec(String[]) using new String[] {"sh", "-c", "sleep 2;"} returns 0 (successful execution). Looking at the Runtime.java and ProcessBuilder.java sources, Runtime.exec(String) splits the string out using a StringTokenizer, which uses default delimiters of " \t\n\r\f". So executing Runtime.exec("sh -c 'sleep 2;'") will break the command string out as the array ["sh", "-c", "'sleep", "2;'"], which contains invalid arguments.

To ensure commands are executed properly, it's best to use Runtime.exec(String[]) instead of Runtime.exec(String).

Your cmd /c start /min file1.bat command string is probably not working when split out to ["cmd", "/c", "start", "/min", "file1.bat"]. The following should work:

Runtime.getRuntime().exec(new String[] {"cmd", "/c", "start /min file1.bat"});
于 2012-04-17T13:20:47.397 回答
1

start接受参数/WAIT

检查start /?更多有用的参数（你可能想要/B而不是/MIN）

于 2012-04-17T13:02:26.773 回答
0

对此没有简单准确的方法。Java 无法控制外部程序（并且您启动了这样的外部程序）。您可以循环尝试从任务管理器中获取任务，如果它失败捕获异常并且您知道它何时终止。

或者你计算你的 batfiles 需要的时间，然后构建一个Thread.sleep();

于 2012-04-17T13:09:28.053 回答
0

The comment mark as an answer is not correct because it is related with Linux not Windows

import java.util.Date;
public class Test {
    public static void main(final String[] args) {
        for (int i = 0; i < 5; i++) {
            System.out.println("Executing command " + i + ": " + (new Date()));
            try {
                final Process p = new ProcessBuilder("sh", "-c", "sleep 2;").redirectErrorStream(true).start();
                p.waitFor();
            } catch (final Throwable t) {
                t.printStackTrace();
            }
        }
    }
}
于 2017-02-08T04:40:12.597 回答