我对.Net Web 服务编程很陌生。我在读取从 Web 服务到客户端的 XML 响应时遇到了麻烦。
在我的网络服务端:Service1.asmx.cs 代码:
[WebMethod(Description = "substruction")]
public double subtract(double i, double j)
{
return i - j;
}
[WebMethod(Description = "getxml")]
public XmlDocument GetXML()
{
StringBuilder sb = new StringBuilder();
XmlWriter writer = XmlWriter.Create(sb);
writer.WriteStartDocument();
writer.WriteStartElement("People");
writer.WriteStartElement("Person");
writer.WriteAttributeString("Name", "Nick");
writer.WriteEndElement();
writer.WriteStartElement("Person");
writer.WriteStartAttribute("Name");
writer.WriteValue("Kevin");
writer.WriteEndAttribute();
writer.WriteEndElement();
writer.WriteEndElement();
writer.WriteEndDocument();
writer.Flush();
XmlDocument xmlDocument = new XmlDocument();
xmlDocument.LoadXml(sb.ToString());
return xmlDocument;
}
在这里,我创建了两种方法来测试响应。在 GetXML 中,我创建了一个非常简单的 XML 并将一个包 XML 返回给客户端。
在我的客户端:
// Add button click function
protected void Button1_Click(object sender, EventArgs e)
{
string selectFlag = selectOper.Value;
localhost.Service1 web = new localhost.Service1(); // Have to be the same name as youre Service1.
if (selectFlag.Equals("+"))
{
Result.Text = (web.addition(double.Parse(Num1.Text), double.Parse(Num2.Text))).ToString();
}
else if (selectFlag.Equals("-"))
{
Result.Text = (web.subtract(double.Parse(Num1.Text), double.Parse(Num2.Text))).ToString();
}
}
protected void Button2_Click(object sender, EventArgs e)
{
localhost.Service1 web2 = new localhost.Service1(); // Can u please do not be so silly, use different instance name here.
Button clickedButton = (Button)sender;
XmlDocument xmltest = new XmlDocument();
xmltest = web2.GetXML();
您可以看到我试图让 web2.GetXML() 将整个 XML 放入 XmlDoucment。但是,它说错误 1 无法将类型“object”隐式转换为“System.Xml.XmlDocument”。存在显式转换(您是否缺少演员表?) C:\Documents and Settings\qili\My Documents\Downloads\WebService3\WebService2\WebService2\Default.aspx.cs 39 24 WebService2
任何提示,我想我做错了什么。但是 Buttom1_Click 方法工作正常。