0

表 1 和表 2:

表 1 和表 2 http://aftabfarda.parsfile.com/1.png

SELECT     *
FROM         (SELECT DISTINCT dbo.tb1.ID, dbo.tb1.name, ROW_NUMBER() OVER (ORDER BY tb1.id DESC) AS row
FROM         dbo.tb1 INNER JOIN
                      dbo.tb2 ON dbo.tb1.ID = dbo.tb2.id_tb1) AS a
WHERE     row BETWEEN 1 AND 7
ORDER BY id DESC

结果:

结果... http://aftabfarda.parsfile.com/3.png

(id 11 重复 3 次)

我怎样才能有这个输出:

ID  name    row
--  ------  ---
11  user11  1
10  user10  2
9   user9   3
8   user8   4
7   user7   5
6   user6   6
5   user5   7
4

2 回答 2

3

您可以在使用子查询distinct之前申请:row_number

select  *
from    (
        select  row_number() over (order by tbl.id desc) as row
        ,       *
        from    (
                select  distinct t1.ID
                ,       tb1.name
                from    dbo.tb1 as t1
                join    dbo.tb2 as t2
                on      t1.ID = t2.id_tb1
                ) as sub_dist
        ) as sub_with_rn
where   row between 1 and 7
于 2012-04-17T07:44:49.317 回答
0

作为@Andomar 建议的替代方案,您可以先使用DENSE_RANK而不是对ROW_NUMBER行进行排名(在子查询中),然后再应用DISTINCT(在外部查询中):

SELECT DISTINCT
  ID,
  name,
  row
FROM (
  SELECT
    t1.ID,
    t1.name,
    DENSE_RANK() OVER (ORDER BY t1.ID DESC) AS row
  FROM dbo.tb1 t1
    INNER JOIN dbo.tb2 t2 ON t1.ID = t2.id_tb1
) AS a
WHERE row BETWEEN 1 AND 7
ORDER BY ID DESC

相似,但不完全相同,尽管两者都可能归结为相同的查询计划,但我不确定。我认为值得测试。

而且,当然,您也可以尝试使用连接而不是正确连接,以 anyIN或的形式EXISTS,首先防止重复:

SELECT
  ID,
  name,
  row
FROM (
  SELECT
    ID,
    name,
    ROW_NUMBER() OVER (ORDER BY ID DESC) AS row
  FROM dbo.tb1
  WHERE ID IN (SELECT id_tb1 FROM dbo.tb2)
  /* Or:
  WHERE EXISTS (
    SELECT *
    FROM dbo.tb2
    WHERE id_tb1 = dbo.tb1.ID
  )
  */
) AS a
WHERE row BETWEEN 1 AND 7
ORDER BY ID DESC
于 2012-04-17T09:17:26.083 回答