我需要将更新事件传达给我的 python 脚本的所有正在运行的实例,并且我希望代码尽可能简单。我在正在运行的进程之间进行通信的经验为零。到目前为止,我一直在读/写配置文件,每个实例都会读取和/或更新这些配置文件。
这是我编写的一些伪代码(有点像一个简单的模板),让我了解如何解决这个问题。请试着帮我填空。请记住,我没有使用套接字、线程等的经验......
import process # imaginary module
class AppA():
def __init__(self):
# Every instance that opens will need to attach
# itself to the "Instance Manager". If no manager
# exists, then we need to spawn it. Only one manager
# will ever exist no matter how many instances are
# running.
try:
hm = process.get_handle(AppA_InstanceManager)
except NoSuchProgError:
hm.spawn_instance(AppA_InstanceManager)
finally:
hm.register(self)
self.instance_manager = hm
def state_update(self):
# This method won't exist in the real code, however,
# it emulates internal state changes for the sake of
# explaination.
#
# When any internal state changes happen, we will then
# propagate the changes outward by calling the
# appropriate method of "self.instance_manager".
self.instance_manager.propagate_state()
def cb_state_update(self):
# Called from the "Instance Manager" only!
#
# This may be as simple as reading a known
# config file. Or could simply pass data
# to this method.
class AppA_InstanceManager():
def __init__(self):
self.instances = []
def register_instance(self, instance):
self.instances.append(instance)
def unregister_instance(self, instance):
# nieve example for now.
self.instances.remove(instance)
def propagate_state(self):
for instance in self.instances:
instance.cb_state_update(data)
if __name__ == '__main__':
app = AppA()
有什么建议么?