android - Android 客户端登录到 Django 服务器，如何通过 crsf :|

Question

我正在构建一个 Android 客户端应用程序来连接到 Django 服务器。这里的问题是我无法登录到我的服务器:(。怎么了，帮帮我:| 这是我的 loginFunction()：

1. 创建一个 DefaultHttpClient：

   DefaultHttpClient httpClientStatic = new DefaultHttpClient();
   

2. 从服务器获取 crsf 的函数：

   public String getCsrfFromUrl(String url) {
       HttpGet httpGet = new HttpGet(url);
   
       HttpResponse httpResponse = httpClientStatic.execute(httpGet);
       HttpEntity httpEntity = httpResponse.getEntity();
       is = httpEntity.getContent();
       List<Cookie> cookies = httpClientStatic.getCookieStore().getCookies();
       if (cookies.isEmpty()) {
           Log.e("COOKIES GET ",  "Empty Cookies");
       } else {
           for (int i = 0; i < cookies.size(); i++) {
               Log.e("COOKIES GET ",  cookies.get(i).getName()+"--"+cookies.get(i).getValue());
           }
       }
       return cookies.get(0).getValue();
   }
   

3. 将用户名、传递、crsf 发布到服务器的功能：

   public JSONObject getJSONFromUrl(String url, List<NameValuePair> params) {
   
       // Making HTTP GET request to get csrfmiddlewaretoken:
       try {
           HttpPost httpPost = new HttpPost(url);
           httpPost.setEntity(new UrlEncodedFormEntity(params));
           Log.e("JSON", "In login user 02.4");
           HttpResponse httpResponse = httpClientStatic.execute(httpPost);
           HttpEntity httpEntity = httpResponse.getEntity();
           is = httpEntity.getContent();
           .....
           //Next is read respone, and return json type
       }
   

4. 登录功能：

   public JSONObject loginUser(String username, String password){
       // Building Parameters
   
       List<NameValuePair> params = new ArrayList<NameValuePair>();
       params.add(new BasicNameValuePair("username", username));
       params.add(new BasicNameValuePair("password", password));
       csrfmiddlewaretoken = new JSONParser().getCsrfFromUrl(loginURL);
       params.add(new BasicNameValuePair("csrfmiddlewaretoken", csrfmiddlewaretoken));
       JSONObject json = jsonParser.getJSONFromUrl(loginURL, params);
       return json;
   }
   

它仍然返回 401 错误 anh 500 状态：|。