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我的过滤系统有问题，我想过滤通知。过滤应该使用每个帖子具有的状态 ID，例如错误报告具有状态 ID nro。6.

这是我使用的 jQuery 脚本：

$(document).ready(function() {
$("#status_option").change(                                                     
    function(){
        var statusValue = $('#status_option option:selected').val();
        if(statusValue == "1"){
            <?php 
                $sql_status1="SELECT * FROM notice, user, status WHERE notice.userID = user.userID AND notice.statusID = status.statusID = '1' ORDER BY noticeID DESC";
                $result_status1=mysql_query($sql_status1);
            ?>
        } 
        else if(statusValue == "2"){
            <?php
                $sql_status2="SELECT * FROM notice, user, status WHERE notice.userID = user.userID AND notice.statusID = status.statusID AND status.statusID = '2' ORDER BY noticeID DESC";
                $result_status2=mysql_query($sql_status2);
            ?>
        }                                       
        else if(statusValue == "3"){
            <?php
                $sql_status3="SELECT * FROM notice, user, status WHERE notice.userID = user.userID AND notice.statusID = status.statusID AND status.statusID =  '3' ORDER BY noticeID DESC";
                $result_status3=mysql_query($sql_status3);
            ?>
        }
        else if(statusValue == "4"){
            <?php
                $sql_status4="SELECT * FROM notice, user, status WHERE notice.userID = user.userID AND notice.statusID = status.statusID AND status.statusID = '4' ORDER BY noticeID DESC";
                $result_status4=mysql_query($sql_status4);
            ?>
        }
        else if(statusValue == "5"){
            <?php
                $sql_status5="SELECT * FROM notice, user, status WHERE notice.userID = user.userID AND notice.statusID = status.statusID AND status.statusID = '5' ORDER BY noticeID DESC";
                $result_status5=mysql_query($sql_status5);
            ?>
        }                                   
        else if(statusValue == "6"){
            <?php
                $sql_status6="SELECT * FROM notice, user, status WHERE notice.userID = user.userID AND notice.statusID = status.statusID AND status.statusID = '6' ORDER BY noticeID DESC";
                $result_status6=mysql_query($sql_status6);
            ?>
        }
        else{
            <?php 
                $sql_default="SELECT * FROM notice, user, status WHERE notice.userID = user.userID AND notice.statusID = status.statusID ORDER BY noticeID DESC";
                $result_default=mysql_query($sql_default);
            ?>
        } 
    }   
);});

从下拉列表中选择状态：

<select id="status_valinta" style="width:210px" >
<option title="css/msdropdown_img/status_all.gif">All posts</option>
<option value="1" title=".../status1.gif">Notification</option>
<option value="2" title=".../status2.gif">Waiting for answer</option>
<option value="3" title=".../status3.gif">Guide</option>
<option value="4" title=".../status4.gif">Document</option>
<option value="5" title=".../status5.gif">Image</option>
<option value="6" title=".../status6.gif">Bug-report</option>

问题是当我从下拉列表中选择我想要的状态时，什么也没有发生。此外，该过滤系统应该通过将过滤后的信息动态地打开到同一页面来工作。

这是显示打印数据的地方：

<table width="100%" id="notices" class="ui-widget ui-widget-content">
    <thead>
        <tr class="ui-widget-header ">
            <th>Subject</th>
            <th>Sender</th>
            <th>Comments</th>
            <th>Timestamp</th>
        </tr>
    </thead>
    <tbody>
        <?php
            while($rows=mysql_fetch_array($result)){ // Starting looping rows
        ?>
            <tr style="background-color:<?php echo $rows['colorCode']; ?>">
                <td>
                    <a class="opener_notice, load_data" href="notice_v2.php?id=<?php echo $rows['noticeID']; ?>">
                    <?php echo $rows['title']; ?>
                </td>
                <td><?php echo $rows['firstname']; ?> <?php echo $rows['lastname']; ?>
                </td>
                <td><?php echo $rows['commentID']; ?></td>
                <td><?php echo date('d.m.Y, H:i:s', strtotime( $rows['sendTime'] )); ?>
                </td>
            </tr>
        <?php
            // Stopping the looping and closing the mysql connection
            } mysql_close();
        ?>
    </tbody>
</table>
4

1 回答 1

0

您应该检查您正在处理的 html 页面的来源....因为我可以看到并理解在此代码段中编写的所有 php 代码将仅在服务器上执行，并且在 jquery 过滤中只会有空格..

虽然你想要达到的目标可以通过这样的方式来实现

$(document).ready(function() {
<?php                   // this code will be executed on the server 
    $sql_status1="SELECT status_id, status_value FROM notice, user, status WHERE notice.userID = user.userID AND notice.statusID = status.statusID ORDER BY noticeID DESC"; // considering status_id, status_value are the required attributes
    $result_status1=mysql_query($sql_status1);
    foreach(result_status1 as $res)
         $json_obj_arr[$res[status_id]] = $res[status_value]
    echo 'var notices = '.json_encode($json_obj_arr).';';  //and we will have a json abject in our html 
?>
var notice_json = $.parseJSON(notices);       //we will parse this object 
$("#status_option").change(                                                     
    function(){
        var statusValue = $('#status_option option:selected').val();
        alert(notice_json.statusValue);   //and directly access the value corresponding to statusValue in the notice_json object
    }) //end on change
})// end document.ready
于 2012-04-16T18:31:17.170 回答