我有一个结构:
template <class T> struct Array{
int days;
T * M;
Array( int size ) : days(size), M(new T[size])
{
}
~Array()
{
delete[] M;
}
};
void currentDay();
void add(int,int,Array &);
和一个班级:
class Expe {
private:
int hk; //HouseKeeping
int fo; //Food
int tr; //Transport
int cl; //Clothing
int tn; //TelNet
int ot; //Others
}
类构造函数是:
Expe::Expe() {
this->hk = hk;
this->fo = fo;
this->tr = tr;
this->cl = cl;
this->tn = tn;
this->ot = ot;
}
问题:在主函数中,我可以使用对象操作结构...例如使用 setObj() 函数,但是当我尝试在 Controller 或 Controller.hi 中定义我的函数时,会出现以下错误:
..\ListStruc.cpp:28:28: error: 'Array' is not a type
..\ListStruc.cpp: In function 'void add(int, int, int)':
..\ListStruc.cpp:31:4: error: request for member 'M' in 'A', which is of non-class type 'int'
编辑:
void add(int cant, int tip,Array A){
//Adds to current day the amount to a specific type
A.M[currentDay]; // i try to use this object.
}