2

我有以下查询： -

select
dbo.table1.service,
dbo.table1.level_3_structure,
Sum(table1.Reduced) as Total_Reduced

from dbo.table1

where 
dbo.table1.Period = 'Cumulative'

Group by 
dbo.table1.service,
dbo.table1.level_3_structure

这导致类似于以下内容：-

service          level_3_structure   Total_Reduced
Service 1            Structure1          11.76
Service 2            Structure2         239.86
Service 3            Structure3         940.29

我有另一个表（表 2），其中包含值 service 和 level_3_structure，还包含一个名为“FTE”的列。

我想要做的是基于服务和 level_3_structure 加入这个表并返回 FTE 的总和。

我尝试了以下查询，但它似乎为每个匹配行重复 table1，导致大约 830 万个结果。

select
dbo.table1.service,
dbo.table1.level_3_structure,
Sum(dbo.table1.Reduced) as Total_Reduced,
Sum(dbo.table2.fte) as 'Total FTE'

from dbo.table1
left join dbo.table2
on dbo.table1.service = dbo.table2.service and
   dbo.table1.level_3_structure = dbo.table2.level_3_structure

where 
dbo.table1.Period = 'Cumulative'

Group by 
dbo.table1.service,
dbo.table1.level_3_structure
4

1 回答 1

5

如果您的第一个查询返回您需要的行，那么您可以将它（而不是 table1）连接到 table2：

select service, level_3_structure, Total_Reduced, sum(fte) as Total_FTE
from (
    select 
    dbo.table1.service, 
    dbo.table1.level_3_structure, 
    Sum(table1.Reduced) as Total_Reduced 

    from dbo.table1 

    where  
    dbo.table1.Period = 'Cumulative' 

    Group by  
    dbo.table1.service, 
    dbo.table1.level_3_structure 
) t1
inner join table2 on t1.service = table2.service 
AND t1.level_3_structure = table2.level_3_structure 

    Group by  
    dbo.table1.service, 
    dbo.table1.level_3_structure

不过，听起来您的 table1 应该有列 fte。

于 2012-04-16T11:13:41.597 回答