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感谢您的小费。也许我可以编辑它以更好地解释它......

我正在为 Google App Engine 编写一个应用程序，我想在其中执行 GQL 查询以获取已提交的每种类型的所有评估。我希望允许用户单击链接来编辑每个单独的评估，然后提交更改。这是我发现的最好的方法......

class EvaluationApproval(webapp.RequestHandler):
   def get(self):
      #search for unapproved general evaluations
      query = db.GqlQuery("SELECT * FROM GeneralAssessmentReport WHERE Approved = False")

      if query.count() != 0:
         for item in query:
            #create a link to edit that item
            self.response.out.write('<a href="generalFromApprove?key=%s">%s</a>' % (item.key(), item.Name))


    #do this for each type of evaluation...

    query = db.GqlQuery("SELECT * FROM HeadNeck WHERE Approved = False")
    if query.count() != 0:
        for item in query:
            self.response.out.write('<a href="headNeckApprove?key=%s">%s</a>' % (item.key(), item.Name))

    query = db.GqlQuery("SELECT * FROM lowerExtremity WHERE Approved = False")
    if query.count() != 0:
        for item in query:
            self.response.out.write('<a href="lowerApprove?key=%s">%s</a>' % (item.key(), item.Name))

所以，当用户点击他们被定向到的链接时......

class GeneralFormApprove(webapp.RequestHandler):
   def get(self):
      # get the correct evaluation to approve
      key = self.request.get('key')
      item = GeneralAssessmentReport.get(key)

      #write out the form with key in the form action!
      self.response.out.write('<form method="POST" action="/generalFormApprove?key=%s">' % key)
      self.response.out.write(GeneralAssessmentReportForm(instance=item))

   def post(self):
      # get the key once more
      key = self.request.get('key')

      data = GeneralAssessmentReportForm(data=self.request.POST,instance=GeneralAssessmentReport.get(key))
      if data.is_valid():
         # save the edited evaluation
         entity = data.save(commit=False)
         entity.put()

然后为每种类型的评估创建一个 WhatFormApprove 类。这有意义吗？您还有其他想法可以实现吗？

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1 回答 1

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对于编辑现有实体，一个好方法是使用包含实体 id 的 url 模式。发布后，您可以使用 id 加载实体，然后在表单的实例参数中使用它。

url 模式类似于：

r'^evaluationapproval/(?P<item_id>[\d]+)/$'


def post(self,item_id=None):
    item = None
    if item_id:
        item = db.get(db.Key.from_path('MyModelKind',int(item_id)))
        #...
于 2012-06-18T17:46:30.883 回答