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我没有太多运气弄清楚如何使用 int 和字符串进行查询。我找到了两个整数的例子,我找到了两个字符串的例子。我尝试了不同的组合,但似乎没有任何效果。以下是我尝试过但没有奏效的两个示例。我究竟做错了什么。我自己使用了 inpspection_id 和 item_name ,它们都可以工作。

尝试1:

public int getId(int inspection_id ,String item_name)throws Exception
{
    Cursor c = db.query(DB_TABLE, new String[] {KEY_INSPECTION_ID, KEY_ITEM_NAME},
            "inspection_id=" + inspection_id +"item_name='"+ item_name + "'", null, null, null, null);
    int id=c.getColumnIndex(KEY_ROWID);
    c.moveToFirst();
    String result=c.getString(id);
    int primId=Integer.parseInt(result);
    c.close();
    return primId;

}

尝试2:

public int getId(int inspection_id ,String item_name)throws Exception
{
    Cursor c = db.query(DB_TABLE, new String[] {KEY_INSPECTION_ID, KEY_ITEM_NAME},
            "inspection_id=" + inspection_id +"AND KEY_ITEM_NAME = ?", new String[]{item_name}, null, null, null);
    int id=c.getColumnIndex(KEY_ROWID);
    c.moveToFirst();
    String result=c.getString(id);
    int primId=Integer.parseInt(result);
    c.close();
    return primId;

}

尝试3:

public int getId(int inspection_id ,String item_name)throws Exception
{
    String s_id= Integer.toString(inspection_id);
    Cursor c = db.query(DB_TABLE, new String[] {KEY_INSPECTION_ID, KEY_ITEM_NAME},
            "KEY_INSPECTION_ID = ? AND KEY_ITEM_NAME = ?",
             new String[] {  s_id, item_name }, null, null, null);
    int id=c.getColumnIndex(KEY_ROWID);
    c.moveToFirst();
    String result=c.getString(id);
    int primId=Integer.parseInt(result);
    c.close();
    return primId;

}
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1 回答 1

2

尝试这种方式,用单引号表示 int 。

"inspection_id='" + inspection_id +"'item_name='"+ item_name + "'"
于 2012-04-15T20:36:02.997 回答