即,我在按钮处理程序中调用了以下代码段:
TextBox1.Text = Application.GetOpenFilename("All files (*.*),*.*", _
1, "Open the Raw Data Files", , False)
If TextBox1.Text = "False" Then TextBox1.Text = ""
错误说:“编译器错误:找不到方法或数据成员”
提前致谢!
Word中没有Application.GetOpenFilename
。
你需要FileDialog
改用。这是一个简单的例子:
Private Sub CommandButton1_Click()
Dim s As Variant
Dim Res As Integer
Dim dlgSaveAs As FileDialog
Set dlgSaveAs = Application.FileDialog( _
FileDialogType:=msoFileDialogSaveAs)
Res = dlgSaveAs.Show
If Not Res = 0 Then
For Each s In dlgSaveAs.SelectedItems 'There is only one
MsgBox s
Next
End If
End Sub