4

我在模型中有这个：

public function index_loop() { 
        $post_user = $this->db->query("SELECT posts.post_title, posts.post_content, posts.post_date, users.username FROM posts LEFT JOIN users ON posts.user_id = users.user_id ORDER BY posts.post_ID DESC");
        //$categories = $this->db->query("SELECT categories.cat_name, categories.cat_id FROM  
        //$comments = $this->db->query("SELECT COUNT(comment_id) FROM comments WHERE
        return $post_user->result_array();
    }

我需要的是显示每个帖子和评论的类别（尽管我想如果我弄清楚类别传递而不是评论是相同的方式）

在查看文件中：

 <?php foreach($posts as $zz) { ?>
         <div class="article">
           <h2><?php echo $zz['post_title']; ?></h2>
           <p>Posted by <a href=""><?php echo $zz['username']; ?></a> | Filed under <a href="#">templates</a>, <a href=>internet</a></p>
            <p><?php echo $zz['post_content']; ?></p>
           <p><a href=>Read more</a> | <a href=>Comments (5)</a> | <?php echo $zz['post_date']; ?></p>
        </div> <?php } ?>

所以，如果我想在每个博客上循环类别，我需要那个博客 ID，如果我从 Model 进行所有查询，我该如何获取它？评论也一样

我做一个大的复杂的数据库查询（这很难，但我可以做到）或者我可以做 2 或 3 个单独的小查询，这很好吗？

4

2 回答 2

2

Codeigniter 允许您将数据库结果作为对象（例如模型对象）返回，这使得数据更易于使用。您可以向Posts表发出初始查询，在结果集中包含该posts.id字段，并将Post_model类的名称传递给$db->query->result()函数以告诉 codeigniter 您希望将结果作为Post_model类的实例返回。

然后，您可以在Post_model类上定义GetCategoriesbypost_id和GetCommentsbypost_id方法，然后调用这些方法来填充您的$categories和$comments集合，以获取Post_model从查询返回的每个。

这是一个例子，我希望它有帮助：

    public class Post_model extends CI_Model
    {

        // All the properties in the Posts table, as well as a couple variables to hold the categories and comments for this Post:
        public $id;
        public $post_title;
        public $post_content;
        public $post_date;
        public $username;        
        public $categories;
        public $comments;

        public function index_loop() 
        { 
                return $this->GetAllPosts();
        }

        // function to get all posts from the database, including comments and categories.
        // returns an array of Post_model objects
        public function GetAllPosts()
        {
                // define an empty array to hold the results of you query.
                $all_posts = array();

                // define your sql query. NOTE the POSTS.ID field has been added to the field list
                $sql = "SELECT posts.id, 
                               posts.post_title, 
                               posts.post_content, 
                               posts.post_date,
                               users.username
                        FROM posts LEFT JOIN users ON posts.user_id = users.user_id
                        ORDER BY posts.post_id DESC";

                // issue the query
                $query = $this->db->query($sql);

                // loop through the query results, passing a string to result() which represents a class to instantiate 
                //for each result object (note: this class must be loaded)

                foreach($query->result("Post_model") as $post)
                {
                        $post->categories = $this->GetPostCategories($post->id);
                        $post->comments = $this->GetPostComments($post->id);
                        $all_posts[] = $post;
                }

                return $all_posts;
        }

        // function to return categories for a given post_id.
        // returns an array of Category_model objects.
        public function GetPostCategories($post_id)
        {
                $sql = "SELECT category.id, ... WHERE post_id = ?";
                $query = $this->db->query($sql, array($post_id));
                $categories = array();
                foreach($query->result("Category_model") as $category)
                {
                        $categories[] = $category;
                }
                return $categories;
        }

        // function to return comments for a given post_id. 
        //returns an array of Comment_model objects
        public function GetPostComments($post_id)
        {
                $sql = "SELECT comment.id, ... WHERE post_id = ?";
                $query = $this->db->query($sql, array($post_id));
                $comments = array();
                foreach($query->result("Comment_model") as $comment)
                {
                        $comments[] = $comment;
                }
                return $comments;
        }    
}

然后，在您看来，您可以将 $posts 数组作为 Post_model 对象而不是 result_arrays 访问：

<?php foreach($posts as $zz) { ?>
         <div class="article">
           <h2><?php echo $zz->post_title; ?></h2>
           <p>Posted by <a href=""><?php echo $zz->username; ?></a> | 

              Filed under 
               <?php foreach($zz->categories as $category) {
                        echo '<a href="#">{$category->name}</a>, ';
                     }
               ?>
           </p>
           <p><?php echo $zz->post_content; ?></p>
           <p><a href=>Read more</a> | <a href=>Comments (5)</a> | <?php echo $zz->post_date; ?></p>
        </div> <?php } ?>

至于效率问题，这将取决于很多因素（数据库是否与 Web 服务器位于同一台机器上？有多少帖子？等等）。单个大型查询通常比几个较小的查询执行得更快，但需要进行分析才能真正确定性能提升是否值得寻求。我总是更喜欢尝试编写可读/可理解的代码，而不是以增加复杂性为代价进行优化。

于 2012-04-16T07:52:36.040 回答
0

你可以做一件事。

制作不同的类别表和评论表。

category_id 将与 post 表中的 category_id 列链接。

在评论表中，创建列 post_id 将与 post 表中的 post_id 链接。

然后您可以通过此扩展查询一次检索所有信息。

$post_user = $this->db->query("SELECT posts.post_title, posts.post_content, posts.post_date, users.username FROM posts LEFT JOIN users ON posts.user_id = users.user_id LEFT JOIN category ON category.category_id = post.category_id ORDER BY posts.post_ID DESC");

在这里你得到了类别。

对于评论，我不确定您希望输出如何。一种方法，正如严所说。如果您可以更具体，我可以建议一些更简单的方法。

于 2012-04-14T15:59:49.910 回答