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我有一个类 DurationFormatter 如下：

import java.util.Date;
import org.joda.time.DateTime;
import org.joda.time.Period;
import org.joda.time.format.PeriodFormatter;
import org.joda.time.format.PeriodFormatterBuilder;

public class DurationFormatter {

  private final static PeriodFormatter DURATION_FORMATTER =
    new PeriodFormatterBuilder().appendYears()
                                .appendSuffix("year", "years")
                                .appendSeparator(" ")
                                .appendMonths()
                                .appendSuffix("month", "months")
                                .appendSeparator(" ")
                                .appendDays()
                                .appendSuffix("day", "days")
                                .appendSeparator(" ")
                                .appendHours()
                                .appendSuffix("hour", "hours")
                                .appendSeparator(" ")
                                .appendMinutes()
                                .appendSuffix("minute", "minutes")
                                .appendSeparator(" ")
                                .appendSeconds()
                                .appendSuffix("second", "seconds")
                                .toFormatter();

  public static String format(Date start) {
    StringBuffer result = new StringBuffer();
    DURATION_FORMATTER.printTo(result,
                               new Period(new DateTime(start), new DateTime()));
    return result.toString();
  }

  public static String format(Date start, Date end) {
    StringBuffer result = new StringBuffer();
    DURATION_FORMATTER.printTo(result,
                               new Period(new DateTime(start),
                                          end == null
                                          ? new DateTime()
                                          : new DateTime(end)));
    return result.toString();
  }

}

这是我的单元测试：

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;

import junit.framework.Assert;

import org.joda.time.DateTime;
import org.joda.time.Period;
import org.junit.Test;

public class DurationFormatterTest {

    @Test
    public void testFormatDate() throws ParseException {

        int years = 0;
        int months = 0;
        int weeks = 0;
        int days = 0;
        int hours = 0;
        int minutes = 0;
        int seconds = 0;
        SimpleDateFormat df = new SimpleDateFormat("dd/MM/yyyy HH:mm:ss");
        String dateString = "07/27/2010 12:07:34";
        Date startDate = (Date) df.parse( dateString );

        // Find duration 1
        String duration1 = DurationFormatter.format(startDate);

        // Parse duration 1 and set values into new Period
        String[] tokens = duration1.split("[ ]");
        for( int index = 0; index < tokens.length; index++ ) {
            String token = tokens[index];
            if( token.contains("years") ) {
                years = Integer.valueOf(token.replace("years", ""));
                System.out.println("Years are: " + years);
            }
            else if( token.contains("months") ) {
                months = Integer.valueOf(token.replace("months", ""));
                System.out.println("Months are: " + months);
            }
            else if( token.contains("days") ) {
                days = Integer.valueOf(token.replace("days", ""));
                System.out.println("Days are: " + days);
            }
            else if( token.contains("hours") ) {
                hours = Integer.valueOf(token.replace("hours", ""));
            }
            else if( token.contains("minutes") ) {
                minutes = Integer.valueOf(token.replace("minutes", ""));
            }
            else if( token.contains("seconds") ) {
                seconds = Integer.valueOf(token.replace("seconds", ""));
            }
        }

        Period period = new Period( years,  months,  weeks,  days,  hours,  minutes,  seconds, 0);

        // User period to initialize new endDate
        DateTime endDate = new DateTime(startDate).plus(period);

        // Find duration 2 using new endDate
        String duration2 = DurationFormatter.format(startDate, endDate.toDate());

        // If the durations are the same, then success.
        Assert.assertEquals(
                "The date of " + duration2
                + " is equal to " + duration1,
                duration1, duration2);
    }
}

结果总是输出错误：

junit.framework.ComparisonFailure：5 天 23 小时 5 分 23 秒的日期等于 1 个月 5 天 23 小时 5 分 23 秒预期：<[1 月 ]5 天 23 小时 5 分钟...> 但为：<[]5 天 23 小时 5 分钟...>

字符串 '[1month ]' 总是丢失。请检查我是否在代码中遗漏了什么？

谢谢

4

1 回答 1

1

在您的代码中，您有.appendSuffix("month", "months")where"month"是单数形式，"months"是复数形式。

您的测试仅解析复数形式：

else if( token.contains("months") ) {
    ...
}

在这种情况下，测试失败，因为它只有 1 个月，因此是单数。

更新您的测试代码以解析单数和复数形式，它应该可以工作！

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于 2012-04-13T04:53:25.147 回答