android - 是否有任何理由从资源中预加载可绘制对象？

Question

Android 是否维护应用程序可绘制资源的内存缓存并重用它们，或者预加载可能动态分配给不同小部件的所有可绘制资源是一种好习惯？

例如：

public static final int[] SETS = {
        R.drawable.set0, R.drawable.set1, R.drawable.set2,
        R.drawable.set3, R.drawable.set4, R.drawable.set5, R.drawable.set6,
        R.drawable.set7, R.drawable.set8, R.drawable.set9, R.drawable.set10};
public Drawable[] sets;

void init() {
    load(sets, SETS);
}

public void load(Drawable[] d, int[] ids) {
    for (int i = 0; i < ids.length; i++) {
        if (ids[i] == 0)
            d[i] = null;
        else
            d[i] = context.getResources().getDrawable(ids[i]);
    }
}

Answer 1

这听起来像是不必要的预优化。但是，android 确实会缓存可绘制对象，因此您不必预先加载它们。相关代码来自ApplicationContext

  /*package*/ Drawable loadDrawable(TypedValue value, int id)
            throws NotFoundException {
        .
        .
        .

        final long key = (((long) value.assetCookie) << 32) | value.data;
        Drawable dr = getCachedDrawable(key);

        if (dr != null) {
            return dr;
        }

        .
        .
        .

        if (dr != null) {
            dr.setChangingConfigurations(value.changingConfigurations);
            cs = dr.getConstantState();
            if (cs != null) {
                if (mPreloading) {
                    sPreloadedDrawables.put(key, cs);
                } else {
                    synchronized (mTmpValue) {
                        //Log.i(TAG, "Saving cached drawable @ #" +
                        //        Integer.toHexString(key.intValue())
                        //        + " in " + this + ": " + cs);
                        mDrawableCache.put(key, new WeakReference<Drawable.ConstantState>(cs));
                    }
                }
            }
        }

        return dr;
    }

    private Drawable getCachedDrawable(long key) {
        synchronized (mTmpValue) {
            WeakReference<Drawable.ConstantState> wr = mDrawableCache.get(key);
            if (wr != null) {   // we have the key
                Drawable.ConstantState entry = wr.get();
                if (entry != null) {
                    //Log.i(TAG, "Returning cached drawable @ #" +
                    //        Integer.toHexString(((Integer)key).intValue())
                    //        + " in " + this + ": " + entry);
                    return entry.newDrawable(this);
                }
                else {  // our entry has been purged
                    mDrawableCache.delete(key);
                }
            }
        }
        return null;
    }