好的......我有一些没有逻辑意义的东西,我希望有人能指出我犯的愚蠢错误。我有一个页面,我希望菜单更改用户是否登录。我正在使用会话变量 $_SESSION['is_logged_in] 来存储登录状态。例如,如果注销,菜单应该显示登录。如果已登录,则相同的菜单应显示已注销。这是逻辑片段中的代码。我提前为所有代码片段道歉,但我想尽可能清楚。请帮忙!
首先,我有一个名为 index.php 的主页,其中有一些空的 div:
<div id="wrapper">
<div id="header">
<h1>My Page</h1>
<div id="navigation">
</div> <!-- end of navigation div -->
</div> <!-- end if header div -->
<p> </p>
<div id="mainContent">
</div><!-- end mainContent div -->
</div> <!-- end wrapper div -->
在此页面(index.php)中,我在文档准备好导航 div 的 jquery 负载:
<script type="text/javascript">
$(document).ready(function(e) {
//load the default menu
$('#navigation').load("menu.php");
});
</script>
好的...现在 menu.php 具有以下 html/php:
<?php
session_start();
include 'php/functions.php';
//following is for debugging, you will see later where this is useful
if (is_logged_in())
{
echo "logged in value: " . is_logged_in() . "<br />";
print_r($_SESSION);
}
else
echo "not sure what is going on</br >";
echo "<br />";
?>
<ul id="menu" class="DropdownMenu">
<li class="sub"><a href="#">Account</a>
<ul>
<?php
//this is where it should show one link or the other based on the value in $_SESSION
if (is_logged_in()) {
echo "<li><a href=\"#\" class=\"ClickLogout\">Log Out</a></li>\n";
} else {
echo "<li><a href=\"#\" class=\"ClickLogin\">Log In</a></li>\n";
}
?>
</ul>
</li>
</ul>
好的......此时,当页面加载时,在菜单顶部我看到调试消息“不确定这里发生了什么”,因为我还没有登录。然后我单击登录链接并通过 ajax 填充 index.php 中的 mainContent div:
这是在 menu.php 中:
$(document).ready(function(e) {
var options = {
target: '#mainContent', // target element(s) to be updated with server response
success: reloadMenu, // post-submit callback
delegation: true
};
// post-submit callback
function reloadMenu(responseText, statusText, xhr, $form) {
$('#navigation').load("menu.php");
};
//set the jquery form plugin for the login form
$('.ContentForm').ajaxForm(options);
//load the login form in the mainContent div
$('#wrapper').on("click", ".ClickLogin", function(e) {
$('#mainContent').load("login.php");
});
});
上面的代码表明,当表单提交成功时,post submit 回调应该重新加载菜单,就像 index.php 文档准备好的初始加载一样。通过调试,我确实看到它确实重新加载了它,但它从未在会话变量中看到任何内容,因此即使我已登录,它仍然显示登录链接而不是注销。
现在,把它们放在一起只是为了表明我没有疯,这是 login.php 中的内容:
<?php
// start the session
session_start();
include 'php/functions.php';
//this sections handles the post of the form
$show_form = true;
if($_SERVER['REQUEST_METHOD'] == "POST")
{
$email = $_POST['email'];
$password = $_POST['password'];
if (authenticate_user($email, $password)) //this will set $_SESSION variables
{
$show_form = false;
echo "Congratulations " . get_user_name() . ", you are logged in <br />";
//following is for debugging, you will see later where this is useful
if (is_logged_in())
{
echo "logged in value: " . is_logged_in() . "<br />";
print_r($_SESSION);
}
else
echo "not sure what is going on</br >";
}
else
{
echo "Invalid email or password. Try again <br />";
}
}
?>
<?php if ($show_form) { ?>
<div id="formContent">
<h2 class="ContentHeader">Log In</h2>
<form id="contentForm" name="registration" class="ContentForm" method="post" action=<?php echo $_SERVER['PHP_SELF']?>>
<p>
<label for="email">Email:</label>
<input type="email" name="email" id="email" required="required">
</p>
<p>
<label for="password">Password:</label>
<input type="password" name="password" id="password" required="required">
</p>
<p>
<input type="submit" name="insert" id="insertLink" value="Submit It" />
<input type="reset" name="cancel" id="cancel" value="Reset" />
</p>
<p>Forgot Password? Click <a href="#">here</a></p>
<p>Need to Register? Click <a class="ClickRegister" href="#">here</a></p>
</form>
我知道这是很多代码,所以我想指出一件事。此时,提交表单时,在#navigation div 中重新加载menu.php,在#mainContent div 中重新加载login.php。两者都在执行完全相同的代码:
//following is for debugging, you will see later where this is useful
if (is_logged_in())
{
echo "logged in value: " . is_logged_in() . "<br />";
print_r($_SESSION);
}
else
echo "not sure what is going on</br >";
当页面在登录表单提交后显示时,在菜单上方显示“不确定发生了什么”,然后是“Array()”,但是在 mainContent 中,它显示“登录值:1”并打印出所有会话值。
为了完整起见,is_logged_in() 函数如下所示:
//return true if the current session is logged in
function is_logged_in()
{
if (array_key_exists('is_logged_in', $_SESSION))
return $_SESSION['is_logged_in'];
}
我在 menu.php 和 login.php 中都有 session_start(),如果我没有,它会在尝试访问 $_SESSION 数组时给我各种其他错误。
我真的希望有人能发现我的错误。请帮忙!
提前致谢。