java - 休眠异常。QuerySyntaxException：意外令牌：HAVING

Question

我尝试使用这个 HQL 查询：

   Result.find("SELECT c, ( 3959 * acos( cos( radians(?) ) * "+
    "cos( radians( c.latitude ) ) *"+
    "cos( radians( c.longitude ) - radians(?) ) +"+
    "sin( radians(?) ) * sin( radians( c.latitude ) ) ) ) " +
    "AS distance FROM City c HAVING distance < ? ORDER BY distance ASC",
    latitude, longitude, latitude, radius).fetch();

但结果是：

IllegalArgumentException occured : org.hibernate.hql.ast.QuerySyntaxException: unexpected token: HAVING near line 1, column 204 [SELECT c, ( 3959 * acos( cos( radians(?) ) * cos( radians( c.latitude ) ) *cos( radians( c.longitude ) - radians(?) ) +sin( radians(?) ) * sin( radians( c.latitude ) ) ) ) AS distance FROM models.City c HAVING distance < ? ORDER BY distance ASC]

Answer 1

尝试在您的查询中更改HAVING为, 。WHERE

Answer 2

仅当您使用 GROUP BY 时才允许使用关键字 HAVING（考虑使用 WHERE 表示 GROUPS）。请参阅 SELECT 语法的参考手册。

Answer 3

唯一的方法是使用本机查询，因为：

• subselect 是不可能的：“请注意，HQL 子查询只能出现在 select 或 where 子句中。” http://docs.jboss.org/hibernate/core/4.3/manual/en-US/html_single/#queryhql-subqueries
• 没有 group by 是不可能的
• 哪里也不可能

Java代码：

@Query(value = "SELECT s.*,\n" +
            "  (\n" +
            "    3959 * acos(\n" +
            "        cos(radians(s.lat))\n" +
            "        * cos(radians(:lat))\n" +
            "        * cos(radians(:lon) - radians(s.lon))\n" +
            "        + sin(radians(s.lat))\n" +
            "          * sin(radians(:lat))\n" +
            "    )\n" +
            "  ) AS distance\n" +
            "FROM Stop s\n" +
            "HAVING distance < 30\n" +
            "ORDER BY distance asc", nativeQuery = true)
    List<Stop> findClosestStops(@Param("lat") Double lat, @Param("lon") Double lon);

另一种方法是返回包含城市+距离的对象列表，但在哪里不可能，但您可以限制结果集

Answer 4

尝试

 select dis.c,dis.distance(
    SELECT c,
     ( 3959 * acos( cos( radians(?) ) *  cos( radians( c.latitude ) ) * 
cos( radians( c.longitude ) - radians(?) ) + sin( radians(?) ) *
 sin( radians( c.latitude ) ) ) )  AS distance FROM City c  ) dis 
where dis.distance<? order by dis.distance ASC

Answer 5

嗯，应该是什么“？” 范围？

如果为真，您应该像这样使用它

HAVING distance < :distance

并使用

query.setParameter("distance", 50);